SQL：獲取父級子項類型= 1且子類型= 2的子項

Question

我在SQL（MySQL環境）中有疑問。 我有兩張桌子：

Airports
--------------------
id    type   city_id
1     2      1
2     3      1
3     4      2


City
----------
id    name
1     Paris
2     Lyon

我想要機場類型為2和3的城市。

我試過了：

SELECT *
FROM city c INNER JOIN airports a ON a.city_id = c.id
WHERE a.type = 1 AND a.type = 2

但它不起作用。

有任何想法嗎 ？

Answer 1

如果你在記錄巴黎之后有兩種不同的類型（1和2），試試這個：

SELECT c.*
FROM city c INNER JOIN 
     airports a ON a.city_id = c.id
WHERE a.type IN (2,3)
HAVING COUNT(DISTINCT a.type)>1

結果：

ID  NAME
1   Paris

在SQL Fiddle中查看結果。

更詳細一點：

SELECT c.id as CID,a.Id as AID,type,city_id,name
FROM city c INNER JOIN
     airports a ON a.city_id=c.id LEFT JOIN
(SELECT c.id
 FROM city c INNER JOIN 
      airports a ON a.city_id = c.id
 WHERE a.type IN (2,3)
 HAVING COUNT(DISTINCT a.type)>1) T ON T.id=c.id
WHERE T.id IS NOT NULL

結果：

CID  AID    TYPE    CITY_ID  NAME
1    1      2       1        Paris
1    2      3       1        Paris

小提琴示例 。

Answer 2

如果您需要存在類型1和2機場的城市，請嘗試使用此查詢：

SELECT * FROM CITY
JOIN
  (
     SELECT CITY_ID FROM Airports WHERE type in (1,2)
     GROUP BY CITY_ID
     HAVING COUNT(DISTINCT type) =2
   ) as A
  ON City.ID=a.City_id

Answer 3

您可以使用子查詢

 SELECT * FROM (
   SELECT *, GROUP_CONCAT(a.type) as tp
   FROM city c INNER JOIN airports a ON a.city_id = c.id
   WHERE a.type IN (1,2)
) tmp WHERE tp = "1,2";

在這里，您可以使用所需的值替換1,2（在子查詢中）

 SELECT * FROM (
   SELECT c.id, c.name, GROUP_CONCAT(a.type) as tp
   FROM city c JOIN airports a ON a.city_id = c.id
   WHERE a.type IN (2,3)
) tmp WHERE tp = "2,3";

上面的一個也返回正確的數據

Answer 4

你能試試嗎？

SELECT *
FROM city c jINNER JOIN (
    SELECT DISTINCT city_id
    FROM airports t1 INNER JOIN airports t2
        ON t1.city_id = t2.city_id
    WHERE t1.type = 1 AND t2.type = 2
) a ON a.city_id = c.id

Answer 5

select c.name from city c where exists
(select * from airport a where a.city_id=c.id and exists
(select * from airport a1 where a1.type=2 and a1.city_id=a.city_id and 
exists(select * from airport a2 where a2.type=3 and a2.city_id=a1.city_id)))

檢查此示例輸出SQL FIDDLE

Answer 6

您可以使用子查詢。試試這個

Select Id,Name from City 
where Id in(Select distinct CityId from Airports where Type in(2,3))