如何在 Swift 中將 plist 作為字典獲取？

Question

我正在使用 Apple 的新Swift編程語言，但遇到了一些問題......

目前我正在嘗試讀取 plist 文件，在 Objective-C 中，我將執行以下操作以將內容作為 NSDictionary 獲取：

NSString *filePath = [[NSBundle mainBundle] pathForResource:@"Config" ofType:@"plist"];
NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:filePath];

如何在 Swift 中將 plist 作為字典獲取？

我假設我可以通過以下方式獲得 plist 的路徑：

let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist")

當這有效時（如果正確？）：如何將內容作為字典獲取？

還有一個更普遍的問題：

可以使用默認的NS*類嗎？ 我想是的……還是我錯過了什么？ 據我所知，默認框架NS*類仍然有效並且可以使用嗎？

Answer 1

你仍然可以在 Swift 中使用 NSDictionaries：

對於 Swift 4

 var nsDictionary: NSDictionary?
 if let path = Bundle.main.path(forResource: "Config", ofType: "plist") {
    nsDictionary = NSDictionary(contentsOfFile: path)
 }

Swift 3+

if let path = Bundle.main.path(forResource: "Config", ofType: "plist"),
   let myDict = NSDictionary(contentsOfFile: path){
    // Use your myDict here
}

和舊版本的 Swift

var myDict: NSDictionary?
if let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist") {
    myDict = NSDictionary(contentsOfFile: path)
}
if let dict = myDict {
    // Use your dict here
}

NSClasses 仍然可用並且完全可以在 Swift 中使用。 我認為他們可能會很快將重點轉移到 swift 上，但目前 swift API 沒有核心 NSClasses 的所有功能。

Answer 2

如果我想將 .plist 轉換為 Swift 字典，我會這樣做：

if let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist") {
  if let dict = NSDictionary(contentsOfFile: path) as? Dictionary<String, AnyObject> {
    // use swift dictionary as normal
  }
}

為 Swift 2.0 編輯：

if let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist"), dict = NSDictionary(contentsOfFile: path) as? [String: AnyObject] {
    // use swift dictionary as normal
}

為 Swift 3.0 編輯：

if let path = Bundle.main.path(forResource: "Config", ofType: "plist"), let dict = NSDictionary(contentsOfFile: path) as? [String: AnyObject] {
        // use swift dictionary as normal
}

Answer 3

在swift 3.0 中從 Plist 讀取。

func readPropertyList() {
        var propertyListFormat =  PropertyListSerialization.PropertyListFormat.xml //Format of the Property List.
        var plistData: [String: AnyObject] = [:] //Our data
        let plistPath: String? = Bundle.main.path(forResource: "data", ofType: "plist")! //the path of the data
        let plistXML = FileManager.default.contents(atPath: plistPath!)!
        do {//convert the data to a dictionary and handle errors.
            plistData = try PropertyListSerialization.propertyList(from: plistXML, options: .mutableContainersAndLeaves, format: &propertyListFormat) as! [String:AnyObject]

        } catch {
            print("Error reading plist: \(error), format: \(propertyListFormat)")
        }
    }

閱讀更多如何在 SWIFT 中使用屬性列表 (.PLIST) 。

Answer 4

斯威夫特 4.0

您現在可以使用 Decodable 協議將 .plist 解碼為自定義結構。 我將介紹一個基本示例，對於更復雜的 .plist 結構，我建議閱讀 Decodable/Encodable（這里有一個很好的資源： https ://benscheirman.com/2017/06/swift-json/）。

首先將結構設置為 .plist 文件的格式。 對於這個例子，我將考慮一個帶有根級別字典和 3 個條目的 .plist：1 個帶有鍵“name”的字符串，1 個帶有鍵“age”的 Int，以及帶有鍵“single”的 1 個布爾值。 這是結構：

struct Config: Decodable {
    private enum CodingKeys: String, CodingKey {
        case name, age, single
    }

    let name: String
    let age: Int
    let single: Bool
}

足夠簡單。 現在是很酷的部分。 使用 PropertyListDecoder 類，我們可以輕松地將 .plist 文件解析為該結構的實例：

func parseConfig() -> Config {
    let url = Bundle.main.url(forResource: "Config", withExtension: "plist")!
    let data = try! Data(contentsOf: url)
    let decoder = PropertyListDecoder()
    return try! decoder.decode(Config.self, from: data)
}

無需擔心更多代碼，一切都在 Swift 中。 更好的是，我們現在有了一個可以輕松使用的 Config 結構體實例：

let config = parseConfig()
print(config.name) 
print(config.age)
print(config.single) 

這會打印 .plist 中“name”、“age”和“single”鍵的值。

Answer 5

此答案使用 Swift 本機對象而不是 NSDictionary。

斯威夫特 3.0

//get the path of the plist file
guard let plistPath = Bundle.main.path(forResource: "level1", ofType: "plist") else { return }
//load the plist as data in memory
guard let plistData = FileManager.default.contents(atPath: plistPath) else { return }
//use the format of a property list (xml)
var format = PropertyListSerialization.PropertyListFormat.xml
//convert the plist data to a Swift Dictionary
guard let  plistDict = try! PropertyListSerialization.propertyList(from: plistData, options: .mutableContainersAndLeaves, format: &format) as? [String : AnyObject] else { return }
//access the values in the dictionary 
if let value = plistDict["aKey"] as? String {
  //do something with your value
  print(value)
}
//you can also use the coalesce operator to handle possible nil values
var myValue = plistDict["aKey"] ?? ""

Answer 6

我一直在使用 Swift 3.0 並希望為更新的語法提供答案。 此外，可能更重要的是，我使用PropertyListSerialization對象來完成繁重的工作，這比僅使用 NSDictionary 靈活得多，因為它允許將 Array 作為 plist 的根類型。

下面是我正在使用的 plist 的屏幕截圖。 它有點復雜，以顯示可用的功率，但這適用於任何允許的 plist 類型組合。

如您所見，我正在使用 String:String 字典數組來存儲網站名稱及其相應 URL 的列表。

如上所述，我正在使用PropertyListSerialization對象為我完成繁重的工作。 此外，Swift 3.0 變得更加“Swifty”，因此所有對象名稱都失去了“NS”前綴。

let path = Bundle.main().pathForResource("DefaultSiteList", ofType: "plist")!
let url = URL(fileURLWithPath: path)
let data = try! Data(contentsOf: url)
let plist = try! PropertyListSerialization.propertyList(from: data, options: .mutableContainers, format: nil)

上面的代碼運行后plist的類型將是Array<AnyObject> ，但我們知道它到底是什么類型，所以我們可以將它轉換為正確的類型：

let dictArray = plist as! [[String:String]]
// [[String:String]] is equivalent to Array< Dictionary<String, String> >

現在我們可以以自然的方式訪問字符串數組的各種屬性：字符串字典。 希望將它們轉換為實際的強類型結構或類；)

print(dictArray[0]["Name"])

Answer 7

最好使用本機字典和數組，因為它們已針對 swift 進行了優化。 話雖如此，您可以快速使用 NS... 類，我認為這種情況是正確的。 以下是您將如何實現它：

var path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist")
var dict = NSDictionary(contentsOfFile: path)

到目前為止（在我看來）這是訪問 plist 的最簡單和最有效的方式，但在未來我希望蘋果將更多功能（例如使用 plist）添加到本機詞典中。

Answer 8

Swift - 讀/寫 plist 和文本文件....

override func viewDidLoad() {
    super.viewDidLoad()

    let fileManager = (NSFileManager .defaultManager())
    let directorys : [String]? = NSSearchPathForDirectoriesInDomains(NSSearchPathDirectory.DocumentDirectory,NSSearchPathDomainMask.AllDomainsMask, true) as? [String]

    if (directorys != nil){
        let directories:[String] = directorys!;
        let dictionary = directories[0]; //documents directory


        //  Create and insert the data into the Plist file  ....
        let plistfile = "myPlist.plist"
        var myDictionary: NSMutableDictionary = ["Content": "This is a sample Plist file ........."]
        let plistpath = dictionary.stringByAppendingPathComponent(plistfile);

        if !fileManager .fileExistsAtPath(plistpath){//writing Plist file
            myDictionary.writeToFile(plistpath, atomically: false)
        }
        else{            //Reading Plist file
            println("Plist file found")

            let resultDictionary = NSMutableDictionary(contentsOfFile: plistpath)
            println(resultDictionary?.description)
        }


        //  Create and insert the data into the Text file  ....
        let textfile = "myText.txt"
        let sampleText = "This is a sample text file ......... "

        let textpath = dictionary.stringByAppendingPathComponent(textfile);
        if !fileManager .fileExistsAtPath(textpath){//writing text file
            sampleText.writeToFile(textpath, atomically: false, encoding: NSUTF8StringEncoding, error: nil);
        } else{
            //Reading text file
            let reulttext  = String(contentsOfFile: textpath, encoding: NSUTF8StringEncoding, error: nil)
            println(reulttext)
        }
    }
    else {
        println("directory is empty")
    }
}

Answer 9

Swift 2.0：訪問 Info.Plist

我有一個名為 CoachMarksDictionary 的字典，在 Info.Plist 中有一個布爾值。 我想訪問 bool 值並使其為真。

let path = NSBundle.mainBundle().pathForResource("Info", ofType: "plist")!
  let dict = NSDictionary(contentsOfFile: path) as! [String: AnyObject]

  if let CoachMarksDict = dict["CoachMarksDictionary"] {
       print("Info.plist : \(CoachMarksDict)")

   var dashC = CoachMarksDict["DashBoardCompleted"] as! Bool
    print("DashBoardCompleted state :\(dashC) ")
  }

寫入 Plist：

來自自定義 Plist：-（從 File-New-File-Resource-PropertyList 創建。添加了三個名為：DashBoard_New、DashBoard_Draft、DashBoard_Completed 的字符串）

func writeToCoachMarksPlist(status:String?,keyName:String?)
 {
  let path1 = NSBundle.mainBundle().pathForResource("CoachMarks", ofType: "plist")
  let coachMarksDICT = NSMutableDictionary(contentsOfFile: path1!)! as NSMutableDictionary
  var coachMarksMine = coachMarksDICT.objectForKey(keyName!)

  coachMarksMine  = status
  coachMarksDICT.setValue(status, forKey: keyName!)
  coachMarksDICT.writeToFile(path1!, atomically: true)
 }

該方法可以稱為

self.writeToCoachMarksPlist(" true - means user has checked the marks",keyName: "the key in the CoachMarks dictionary").

Answer 10

通過尼克的回答轉換為便利擴展：

extension Dictionary {
    static func contentsOf(path: URL) -> Dictionary<String, AnyObject> {
        let data = try! Data(contentsOf: path)
        let plist = try! PropertyListSerialization.propertyList(from: data, options: .mutableContainers, format: nil)

        return plist as! [String: AnyObject]
    }
}

用法：

let path = Bundle.main.path(forResource: "plistName", ofType: "plist")!
let url = URL(fileURLWithPath: path)
let dict = Dictionary<String, AnyObject>.contentsOf(path: url)

我願意打賭它也可以為數組創建類似的擴展

Answer 11

由於這個答案還沒有出現，只是想指出您還可以使用 infoDictionary 屬性將信息 plist 作為字典Bundle.main.infoDictionary 。

盡管如果您只對信息 plist 中的特定項目感興趣，像Bundle.main.object(forInfoDictionaryKey: kCFBundleNameKey as String)可能會更快。

// Swift 4

// Getting info plist as a dictionary
let dictionary = Bundle.main.infoDictionary

// Getting the app display name from the info plist
Bundle.main.infoDictionary?[kCFBundleNameKey as String]

// Getting the app display name from the info plist (another way)
Bundle.main.object(forInfoDictionaryKey: kCFBundleNameKey as String)

Answer 12

斯威夫特 5

如果你想獲取某個鍵的特定值，那么我們可以使用下面的擴展，它在 Bundle 上使用infoDictionary屬性。

Bundle.main.infoDictionary可用於獲取表單字典中的所有info.plist值，因此我們可以使用 Bundle 上的object(forInfoDictionaryKey: key)方法直接查詢

extension Bundle {
    static func infoPlistValue(forKey key: String) -> Any? {
        guard let value = Bundle.main.object(forInfoDictionaryKey: key) else {
           return nil
        }
        return value
    }
}

用法

guard let apiURL = Bundle.infoPlistValue(forKey: "API_URL_KEY") as? String else { return }

Answer 13

實際上可以在 1 行中完成

    var dict = NSDictionary(contentsOfFile: NSBundle.mainBundle().pathForResource("Config", ofType: "plist"))

Answer 14

您可以通過以下方式閱讀 SWIFT 語言中的 plist：

let path = NSBundle.mainBundle().pathForResource("PriceList", ofType: "plist")
let dict = NSDictionary(contentsOfFile: path)

讀取單個字典值：

let test: AnyObject = dict.objectForKey("index1")

如果你想在 plist 中獲得完整的多維字典：

let value: AnyObject = dict.objectForKey("index2").objectForKey("date")

這是plist：

<plist version="1.0">
<dict>
<key>index2</key>
<dict>
    <key>date</key>
    <string>20140610</string>
    <key>amount</key>
    <string>110</string>
</dict>
<key>index1</key>
<dict>
    <key>amount</key>
    <string>125</string>
    <key>date</key>
    <string>20140212</string>
</dict>
</dict>
</plist>

Answer 15

就我而言，我創建了一個名為appSettings的NSDictionary並添加了所有需要的鍵。 對於這種情況，解決方法是：

if let dict = NSBundle.mainBundle().objectForInfoDictionaryKey("appSettings") {
  if let configAppToken = dict["myKeyInsideAppSettings"] as? String {

  }
}

Answer 16

您可以使用它，我在 github https://github.com/DaRkD0G/LoadExtension 中為 Dictionary 創建了一個簡單的擴展

extension Dictionary {
    /**
        Load a Plist file from the app bundle into a new dictionary

        :param: File name
        :return: Dictionary<String, AnyObject>?
    */
    static func loadPlistFromProject(filename: String) -> Dictionary<String, AnyObject>? {

        if let path = NSBundle.mainBundle().pathForResource("GameParam", ofType: "plist") {
            return NSDictionary(contentsOfFile: path) as? Dictionary<String, AnyObject>
        }
        println("Could not find file: \(filename)")
        return nil
    }
}

你可以用它來加載

/**
  Example function for load Files Plist

  :param: Name File Plist
*/
func loadPlist(filename: String) -> ExampleClass? {
    if let dictionary = Dictionary<String, AnyObject>.loadPlistFromProject(filename) {
        let stringValue = (dictionary["name"] as NSString)
        let intergerValue = (dictionary["score"] as NSString).integerValue
        let doubleValue = (dictionary["transition"] as NSString).doubleValue

        return ExampleClass(stringValue: stringValue, intergerValue: intergerValue, doubleValue: doubleValue)
    }
    return nil
}

Answer 17

這是一個更短的版本，基於@connor 的回答

guard let path = Bundle.main.path(forResource: "GoogleService-Info", ofType: "plist"),
    let myDict = NSDictionary(contentsOfFile: path) else {
    return nil
}

let value = dict.value(forKey: "CLIENT_ID") as! String?

Answer 18

斯威夫特 3.0

if let path = Bundle.main.path(forResource: "config", ofType: "plist") {
    let dict = NSDictionary(contentsOfFile: path)

    // use dictionary
}

在我看來，這是最簡單的方法。

Answer 19

第 1 步：在 swift 3+ 中簡單快速地解析 plist

extension Bundle {

    func parsePlist(ofName name: String) -> [String: AnyObject]? {

        // check if plist data available
        guard let plistURL = Bundle.main.url(forResource: name, withExtension: "plist"),
            let data = try? Data(contentsOf: plistURL)
            else {
                return nil
        }

        // parse plist into [String: Anyobject]
        guard let plistDictionary = try? PropertyListSerialization.propertyList(from: data, options: [], format: nil) as? [String: AnyObject] else {
            return nil
        }

        return plistDictionary
    }
}

第2步：如何使用：

Bundle().parsePlist(ofName: "Your-Plist-Name")

Answer 20

我創建了一個簡單的Dictionary初始值設定項來替換NSDictionary(contentsOfFile: path) 。 只需刪除NS 。

extension Dictionary where Key == String, Value == Any {

    public init?(contentsOfFile path: String) {
        let url = URL(fileURLWithPath: path)

        self.init(contentsOfURL: url)
    }

    public init?(contentsOfURL url: URL) {
        guard let data = try? Data(contentsOf: url),
            let dictionary = (try? PropertyListSerialization.propertyList(from: data, options: [], format: nil) as? [String: Any]) ?? nil
            else { return nil }

        self = dictionary
    }

}

你可以像這樣使用它：

let filePath = Bundle.main.path(forResource: "Preferences", ofType: "plist")!
let preferences = Dictionary(contentsOfFile: filePath)!
UserDefaults.standard.register(defaults: preferences)

Answer 21

基於https://stackoverflow.com/users/3647770/ashok-r上面的回答，已解析 Swift 4.0 iOS 11.2.6 列表和解析它的代碼。

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<array>
  <dict>
    <key>identity</key>
    <string>blah-1</string>
    <key>major</key>
    <string>1</string>
    <key>minor</key>
    <string>1</string>
    <key>uuid</key>
    <string>f45321</string>
    <key>web</key>
    <string>http://web</string>
</dict>
<dict>
    <key>identity</key>
    <string></string>
    <key>major</key>
    <string></string>
    <key>minor</key>
    <string></string>
    <key>uuid</key>
    <string></string>
    <key>web</key>
    <string></string>
  </dict>
</array>
</plist>

do {
   let plistXML = try Data(contentsOf: url)
    var plistData: [[String: AnyObject]] = [[:]]
    var propertyListFormat =  PropertyListSerialization.PropertyListFormat.xml
        do {
            plistData = try PropertyListSerialization.propertyList(from: plistXML, options: .mutableContainersAndLeaves, format: &propertyListFormat) as! [[String:AnyObject]]

        } catch {
            print("Error reading plist: \(error), format: \(propertyListFormat)")
        }
    } catch {
        print("error no upload")
    }

Answer 22

這是我找到的解決方案：

let levelBlocks = NSDictionary(contentsOfFile: NSBundle.mainBundle().pathForResource("LevelBlocks", ofType: "plist"))
let test: AnyObject = levelBlocks.objectForKey("Level1")
println(test) // Prints the value of test

我將test類型設置為AnyObject以AnyObject有關可能發生的意外推斷的警告。

此外，它必須在類方法中完成。

要訪問和保存已知類型的特定值：

let value = levelBlocks.objectForKey("Level1").objectForKey("amount") as Int
println(toString(value)) // Converts value to String and prints it

Answer 23

我使用 swift 字典，但在我的文件管理器類中將它們與 NSDictionaries 相互轉換，如下所示：

    func writePlist(fileName:String, myDict:Dictionary<String, AnyObject>){
        let docsDir:String = dirPaths[0] as String
        let docPath = docsDir + "/" + fileName
        let thisDict = myDict as NSDictionary
        if(thisDict.writeToFile(docPath, atomically: true)){
            NSLog("success")
        } else {
            NSLog("failure")
        }

    }
    func getPlist(fileName:String)->Dictionary<String, AnyObject>{
        let docsDir:String = dirPaths[0] as String
        let docPath = docsDir + "/" + fileName
        let thisDict = NSDictionary(contentsOfFile: docPath)
        return thisDict! as! Dictionary<String, AnyObject>
    }

這似乎是最不麻煩的讀寫方式，但讓我的其余代碼盡可能保持快速。

Answer 24

Plist是我為處理屬性列表而制作的一個簡單的 Swift 枚舉。

// load an applications info.plist data

let info = Plist(NSBundle.mainBundle().infoDictionary)
let identifier = info["CFBundleIndentifier"].string!

更多例子：

import Plist

// initialize using an NSDictionary
// and retrieve keyed values

let info = Plist(dict)
let name = info["name"].string ?? ""
let age = info["age"].int ?? 0


// initialize using an NSArray
// and retrieve indexed values

let info = Plist(array)
let itemAtIndex0 = info[0].value


// utility initiaizer to load a plist file at specified path
let info = Plist(path: "path_to_plist_file")

// we support index chaining - you can get to a dictionary from an array via
// a dictionary and so on
// don't worry, the following will not fail with errors in case
// the index path is invalid
if let complicatedAccessOfSomeStringValueOfInterest = info["dictKey"][10]["anotherKey"].string {
  // do something
}
else {
  // data cannot be indexed
}

// you can also re-use parts of a plist data structure

let info = Plist(...)
let firstSection = info["Sections"][0]["SectionData"]
let sectionKey = firstSection["key"].string!
let sectionSecret = firstSection["secret"].int!

Plist.swift

Plist 本身非常簡單，這里是它的列表，以防您直接參考。

//
//  Plist.swift
//


import Foundation


public enum Plist {

    case dictionary(NSDictionary)
    case Array(NSArray)
    case Value(Any)
    case none

    public init(_ dict: NSDictionary) {
        self = .dictionary(dict)
    }

    public init(_ array: NSArray) {
        self = .Array(array)
    }

    public init(_ value: Any?) {
        self = Plist.wrap(value)
    }

}


// MARK:- initialize from a path

extension Plist {

    public init(path: String) {
        if let dict = NSDictionary(contentsOfFile: path) {
            self = .dictionary(dict)
        }
        else if let array = NSArray(contentsOfFile: path) {
            self = .Array(array)
        }
        else {
            self = .none
        }
    }

}


// MARK:- private helpers

extension Plist {

    /// wraps a given object to a Plist
    fileprivate static func wrap(_ object: Any?) -> Plist {

        if let dict = object as? NSDictionary {
            return .dictionary(dict)
        }
        if let array = object as? NSArray {
            return .Array(array)
        }
        if let value = object {
            return .Value(value)
        }
        return .none
    }

    /// tries to cast to an optional T
    fileprivate func cast<T>() -> T? {
        switch self {
        case let .Value(value):
            return value as? T
        default:
            return nil
        }
    }
}

// MARK:- subscripting

extension Plist {

    /// index a dictionary
    public subscript(key: String) -> Plist {
        switch self {

        case let .dictionary(dict):
            let v = dict.object(forKey: key)
            return Plist.wrap(v)

        default:
            return .none
        }
    }

    /// index an array
    public subscript(index: Int) -> Plist {
        switch self {
        case let .Array(array):
            if index >= 0 && index < array.count {
                return Plist.wrap(array[index])
            }
            return .none

        default:
            return .none
        }
    }

}


// MARK:- Value extraction

extension Plist {

    public var string: String?       { return cast() }
    public var int: Int?             { return cast() }
    public var double: Double?       { return cast() }
    public var float: Float?         { return cast() }
    public var date: Date?         { return cast() }
    public var data: Data?         { return cast() }
    public var number: NSNumber?     { return cast() }
    public var bool: Bool?           { return cast() }


    // unwraps and returns the underlying value
    public var value: Any? {
        switch self {
        case let .Value(value):
            return value
        case let .dictionary(dict):
            return dict
        case let .Array(array):
            return array
        case .none:
            return nil
        }
    }

    // returns the underlying array
    public var array: NSArray? {
        switch self {
        case let .Array(array):
            return array
        default:
            return nil
        }
    }

    // returns the underlying dictionary
    public var dict: NSDictionary? {
        switch self {
        case let .dictionary(dict):
            return dict
        default:
            return nil
        }
    }

}


// MARK:- CustomStringConvertible

extension Plist : CustomStringConvertible {
    public var description:String {
        switch self {
        case let .Array(array): return "(array \(array))"
        case let .dictionary(dict): return "(dict \(dict))"
        case let .Value(value): return "(value \(value))"
        case .none: return "(none)"
        }
    }
}

Answer 25

斯威夫特 3.0

如果你想從 .plist 讀取一個“二維數組”，你可以這樣嘗試：

if let path = Bundle.main.path(forResource: "Info", ofType: "plist") {
    if let dimension1 = NSDictionary(contentsOfFile: path) {
        if let dimension2 = dimension1["key"] as? [String] {
            destination_array = dimension2
        }
    }
}

Answer 26

如果您有 Info.plist，則使用

Bundle.main.infoDictionary

Answer 27

訪問 plist 文件的簡單結構（Swift 2.0）

struct Configuration {      
  static let path = NSBundle.mainBundle().pathForResource("Info", ofType: "plist")!
  static let dict = NSDictionary(contentsOfFile: path) as! [String: AnyObject]

  static let someValue = dict["someKey"] as! String
}

用法：

print("someValue = \(Configuration.someValue)")