將數據發送到Fragment而不是帶有Parcelable對象的Activity

Question

我想將數據發送到我已創建的Parcelable類的Fragment中。

我知道這是使用Activity（ObjectA是可擴展Parcelable的類）時的處理方式：

ObjectA obj = new ObjectA();   
// Set values etc.   
Intent i = new Intent(this, MyActivity.class); 
i.putExtra("com.package.ObjectA", obj);   
startActivity(i); 

但是由於您無法將Intent與Fragments配合使用，因此我不知道如何執行此操作。

我什至可以使用Parcelable類嗎？ 如果沒有，我應該怎么用？ 我有可能，怎么辦？

編輯/更新：

我已經為您提供了一些建議，但仍然無法獲得所有建議。

這是我們用來創建列表視圖的片段：

package com.tsjd.HotMeals;

import java.util.ArrayList;

import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ListView;

import com.example.tabtest.R;

public class RecipeListViewFragment extends Fragment {

    ArrayList<String> titles;
    ArrayList<String> descriptions;
    ArrayList<String> images;


    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        RecipeListViewParcer object = getArguments().getParcelable("extraObject");
        titles = object.getTitles();
        descriptions = object.getDescriptions();
        images = object.getImages();
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        View v = inflater.inflate(R.layout.fragment_recipelistview, container,
                false);

        final ListView listview = (ListView) v.findViewById(R.id.listview);


        RecipeListViewAdapter adapter = new RecipeListViewAdapter(
                getActivity(), titles);
        listview.setAdapter(adapter);

        return v;
    }

    public void onListItemClick(ListView l, View v, int position, long id) {
        // do something with the data
    }
}

我想將此ListView用於不同的事物，因此我希望能夠將三個ArrayList發送給它。 為此，我制作了一個實現Parcelable的類，就是這樣：

package com.tsjd.HotMeals;

import java.util.ArrayList;

import android.os.Parcel;
import android.os.Parcelable;

public class RecipeListViewParcer implements Parcelable{

    private ArrayList<String> titles;
    private ArrayList<String> descriptions;
    private ArrayList<String> images;

     @SuppressWarnings("unchecked")
    private RecipeListViewParcer(Parcel in) {
            titles = (ArrayList<String>) in.readSerializable();
            descriptions = (ArrayList<String>) in.readSerializable();
            images = (ArrayList<String>) in.readSerializable();
        }

    public int describeContents() {
        return 0;
    }

    public ArrayList<String> getTitles()
    {
        return titles;
    }

    public void setTitles(ArrayList<String> titles){
        this.titles = titles;
    }

    public ArrayList<String> getDescriptions()
    {
        return descriptions;
    }

    public void setDescriptions(ArrayList<String> descriptions){
        this.descriptions = descriptions;
    }

    public ArrayList<String> getImages()
    {
        return images;
    }

    public void setImages(ArrayList<String> images){
        this.images = images;
    }

    public void writeToParcel(Parcel out, int flags) {
        out.writeSerializable(titles);
        out.writeSerializable(descriptions);
        out.writeSerializable(images);
    }

    public static final Parcelable.Creator<RecipeListViewParcer> CREATOR
            = new Parcelable.Creator<RecipeListViewParcer>() {
        public RecipeListViewParcer createFromParcel(Parcel in) {
            return new RecipeListViewParcer(in);
        }

        public RecipeListViewParcer[] newArray(int size) {
            return new RecipeListViewParcer[size];
        }
    };



}

最后，這是一個使用listview顯示喜歡的食譜的片段，在這里我想發送三個ArrayList，這是當前唯一有錯誤的代碼。 我不知道如何為我的Parcelable類的構造函數聲明所需的Parcel，該如何處理？ （我還沒有在ArrayLists中放任何東西，但是我希望這個想法很清楚）。

package com.tsjd.HotMeals;

import java.util.ArrayList;

import android.os.Bundle;
import android.os.Parcel;
import android.support.v4.app.Fragment;
import android.support.v4.app.FragmentManager;
import android.support.v4.app.FragmentTransaction;

public class MyRecipesFragment extends Fragment {


    ArrayList<String> titles = new ArrayList<String>();
    ArrayList<String> descriptions = new ArrayList<String>();
    ArrayList<String> images = new ArrayList<String>();



    Parcel in = new Parcel();

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        FragmentManager fragmentManager = getFragmentManager();
        FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
        Fragment fragment = new RecipeListViewFragment();

        RecipeListViewParcer obj = new RecipeListViewParcer(in);

        obj.setDescriptions(descriptions);
        obj.setTitles(titles);
        obj.setImages(images);

        Bundle bundle = new Bundle();
        bundle.putParcelable("extraObject", obj);
        fragment.setArguments(bundle);

        fragmentTransaction.commit();
    }

}

Answer 1

您必須使用FragmentManager：

發送活動中的3個ArrayList：

  FragmentManager fragmentManager = getFragmentManager(); FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction(); Fragment fragment = new ViewControllerFragment(); ObjectA obj = new ObjectA(); Bundle bundle = new Bundle(); bundle.putStringArrayList("Titles", obj.getTitles()); bundle.putStringArrayList("Descriptions", obj.getDescriptions()); bundle.putStringArrayList("Images", obj.getImages()); fragment.setArguments(bundle); fragmentTransaction.commit(); 

獲取片段中的對象：

Bundle bundle = getArguments();                    
 titles = bundle.getStringArrayList("Titles");            
descriptions= bundle.getStringArrayList("Descriptions");            
images= bundle.getStringArrayList("Images");

或者只是嘗試其他帖子： 將數據從活動發送到android中的片段