如何將子視圖設置為第一響應者？

Question

我試圖在單擊關閉按鈕時關閉圖像視圖。但是按鈕不響應觸摸事件。 這是我的代碼：

-(void)imageTouchUP:(id)sender
{
    UIImageView *imageView=[[UIImageView alloc]initWithFrame:CGRectInset(self.view.bounds, 30 , 30)];
    imageView.image=self.testimonialImage;
    imageView.tag=1;
    UIButton *closeButton=[UIButton buttonWithType:UIButtonTypeCustom];
    closeButton.frame=CGRectMake(0, 0, 20, 20);
    [closeButton setImage:[UIImage imageNamed:@"close.jpg"] forState:UIControlStateNormal];
    [closeButton addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchUpInside];
    [imageView addSubview:closeButton];
    [self.view addSubview:imageView];
}

-(void)buttonClicked:(id)sender
{
    UIView *subView=[self.view viewWithTag:1];
    [subView removeFromSuperview];
}

Answer 1

為了使UIImageView處理觸摸，您需要將userInteractionEnabled設置為YES，它默認為NO。 嘗試：

[imageView setUserInteractionEnabled:YES]; 

參考

Answer 2

UIImageView userInteractionEnabled有1個屬性，其值默認為NO。 所以在你的代碼中添加

UIImageView *imageView=[[UIImageView alloc]initWithFrame:CGRectInset(self.view.bounds, 30 , 30)];
imageView.userInteractionEnabled = YES;

Answer 3

也許在您的self.view中還有另一個帶有tag = 1的視圖。 請嘗試編輯這樣單擊的按鈕：

- (void) buttonClicked:(UIButton *)btn
{
    UIView *view = btn.superview;
    if ([view isKindOfClass:[UIImageView class]]) {
        [view removeFromSuperview];
    }
}