[英]Trouble Writing to file in java
嘿,我試圖寫入文件,但是在寫入文本文件每一行的那一行上卻出現錯誤,無法找出任何幫助,將非常感謝The Writer Code。
public static void stuIDWrite() throws IOException
{
Writer writer = null;
try {
writer = new BufferedWriter(new OutputStreamWriter(
new FileOutputStream("Res/stuIDSorted.txt")));
} catch (IOException ex) {
// report
} finally {
try {writer.close();} catch (Exception ex) {}
}
int i = 0;
while (i <= stuArrayIdSort.length + 1)
{
ln = stuArrayIdSort[i].getStuLastName();
fn = stuArrayIdSort[i].getStuFirstName();
pn = stuArrayIdSort[i].getStuFirstName();
id = stuArrayIdSort[i].getStuId();
ft = stuArrayIdSort[i].getFTime();
phn =stuArrayIdSort[i].getPhoneNum();
lj = stuArrayIdSort[i].getLovJava();
con = stuArrayIdSort[i].getCont();
writer.write(ln + "," + fn + "," + pn + ","+ id + "," + ft + "," + phn + "," + lj + "," + con + "\n");
writer.close();
i++;
}
完整代碼
import java.io.*;
import java.util.*;
public class StudentMain {
/**
* @param args
*/
//array and sorting variables
public static studentConstructor[] stuArrayOrig = new studentConstructor[23];
private static studentConstructor[] stuArrayIdSort = new studentConstructor[23];
private static studentConstructor[] stuArrayNameSort = new studentConstructor[23];
private static int lineCount = 0;
private static int nElms = 0;
//writer
//studentConstructor variables
public static String fn; //First Name
public static String ln; //Last Name
public static String pn; //Preferred Name
public static int id; //Student Id Number
public static boolean ft;//Full-time Boolean
public static int phn; //Student Phone Number
public static boolean lj;//Loving java Boolean
public static String con;//Continuing
File idSort = new File("stuListSortID.txt");
public static void StuRead()
{
Scanner inFile = null;
try
{
inFile = new Scanner
(new FileReader("Res/students.txt"));
}
catch (FileNotFoundException e)
{
// TODO Auto-generated catch block
System.out.println("File Not Found");
e.printStackTrace();
}
while (inFile.hasNextLine()){
inFile.useDelimiter(",|\\n"); //breaks the lines into single info
ln = inFile.next();
System.out.println(ln);
fn = inFile.next();
System.out.println(fn);
pn = inFile.next();
System.out.println(pn);
id = inFile.nextInt();
System.out.println(id);
ft = inFile.nextBoolean();
System.out.println(ft);
phn = inFile.nextInt();
System.out.println(phn);
lj = inFile.nextBoolean();
System.out.println(lj);
con = inFile.next();
System.out.println(con);
studentConstructor st = new studentConstructor(ln, fn, pn, id, ft, phn, lj, con);
stuArrayOrig[lineCount] = st;
inFile.nextLine();
System.out.println(stuArrayOrig[lineCount]);
lineCount++;
}
//setting info into other arrays
stuArrayIdSort = stuArrayOrig;
stuArrayNameSort = stuArrayOrig;
System.out.println("orig array length" + stuArrayOrig.length);
System.out.println("id array length" + stuArrayIdSort.length);
System.out.println("name array length" + stuArrayNameSort.length);
System.out.println("number of file lines" + lineCount);
inFile.close();
}
public static void stuIdSort()
{
studentConstructor temp;
boolean sorted = false;
while (sorted == false)
{ sorted=true;
for (int i=0; i<stuArrayIdSort.length-1 ; i++)
{
if(stuArrayIdSort[i].getStuId() > stuArrayIdSort[i+1].getStuId())
{
temp = stuArrayIdSort[i+1];
stuArrayIdSort[i+1] = stuArrayIdSort[i];
stuArrayIdSort[i] = temp;
sorted=false;
}
}
}
for(int i=0; i<stuArrayIdSort.length; i++)
{
int getSC = stuArrayIdSort[i].studentId;
System.out.println("number of swaps " + i+1 +" " +getSC);
}
}
//stuArrayIdSort[i].getStuLastName(),stuArrayIdSort[i].getStuFirstName(),stuArrayIdSort[i].getPrefName(),stuArrayIdSort[i].getStuId(),stuArrayIdSort[i].getFTime(),stuArrayIdSort[i].getPhoneNum(),stuArrayIdSort[i].getLovJava(),stuArrayIdSort[i].getCont()
public static void stuIDWrite() throws IOException
{
Writer writer = null;
try {
writer = new BufferedWriter(new OutputStreamWriter(
new FileOutputStream("Res/stuIDSorted.txt")));
} catch (IOException ex) {
// report
} finally {
try {writer.close();} catch (Exception ex) {}
}
int i = 0;
while (i <= stuArrayIdSort.length + 1)
{
ln = stuArrayIdSort[i].getStuLastName();
fn = stuArrayIdSort[i].getStuFirstName();
pn = stuArrayIdSort[i].getStuFirstName();
id = stuArrayIdSort[i].getStuId();
ft = stuArrayIdSort[i].getFTime();
phn =stuArrayIdSort[i].getPhoneNum();
lj = stuArrayIdSort[i].getLovJava();
con = stuArrayIdSort[i].getCont();
writer.write(ln + "," + fn + "," + pn + ","+ id + "," + ft + "," + phn + "," + lj + "," + con + "\n");
writer.close();
i++;
}
}
public static void stuNameSort()
{
}
public static void stuNameWrire()
{
}
}
//lastName, firstName, perName, studentId, fulltime,
好的,這是您應該做的:
發生的事情是您在實際上無法執行任何操作之前將其關閉。 因此,讓您將finally子句移到所有內容的末尾:
public static void stuIDWrite() throws IOException
{
Writer writer = null;
try {
writer = new BufferedWriter(new OutputStreamWriter(
new FileOutputStream("Res/stuIDSorted.txt")));
int i = 0;
while (i <= stuArrayIdSort.length + 1)
{
ln = stuArrayIdSort[i].getStuLastName();
fn = stuArrayIdSort[i].getStuFirstName();
pn = stuArrayIdSort[i].getStuFirstName();
id = stuArrayIdSort[i].getStuId();
ft = stuArrayIdSort[i].getFTime();
phn =stuArrayIdSort[i].getPhoneNum();
lj = stuArrayIdSort[i].getLovJava();
con = stuArrayIdSort[i].getCont();
writer.write(ln + "," + fn + "," + pn + ","+ id + "," + ft + "," + phn + "," + lj + "," + con + "\n");
i++;
}
} catch (IOException ex) {
// report
} finally {
try {writer.close();} catch (Exception ex) {}
}
我不確定您是否了解try ... catch ...最終的工作方式。 這是您所擁有的:
Writer writer = null;
try {
writer = new BufferedWriter(new OutputStreamWriter(
new FileOutputStream("Res/stuIDSorted.txt")));
} catch (IOException ex) {
// report
} finally {
>>>>>>> **try {writer.close();} catch (Exception ex) {}**
}
int i = 0;
while (i <= stuArrayIdSort.length + 1)
{
//bunch of stuff
writer.write(...);
>>>>>>> **writer.close();**
i++;
}
}
在甚至還沒有使用完寫入器ONCE之前就將其關閉(最終,該塊將在try塊之后執行),然后在循環內關閉ONCE。 因此,如果代碼能夠以某種方式使其通過finally塊中的writer.close(),它將永遠不會使它多次通過循環。
不必關閉BufferedWriter。 該類確保在內部將其關閉。
如果您使用的是Java 7,則可能要考慮使用“ try-with-resources”語法,在這種情況下,它可以大大簡化文件處理的正確實現。 您的原始代碼有一些問題,但是即使無法接受,也有一些問題,我相信在無法打開文件(未經驗證)的情況下,會導致NullPointerException
。
我認為您的while循環邊界條件也可能有一些問題。 我將while
循環更改為更傳統的for
循環。 請記住,Java數組元素的范圍是0
到array.length - 1
包括array.length - 1
。
public static void stuIDWrite() throws IOException
{
try (FileWriter writer = new FileWriter("Res/stuIDSorted.txt"))
{
for (int i = 0; i < stuArrayIdSort.length; ++i)
{
ln = stuArrayIdSort[i].getStuLastName();
fn = stuArrayIdSort[i].getStuFirstName();
pn = stuArrayIdSort[i].getStuFirstName();
id = stuArrayIdSort[i].getStuId();
ft = stuArrayIdSort[i].getFTime();
phn = stuArrayIdSort[i].getPhoneNum();
lj = stuArrayIdSort[i].getLovJava();
con = stuArrayIdSort[i].getCont();
writer.write(ln + "," + fn + "," + pn + "," + id + "," + ft + "," + phn + "," + lj + "," + con + "\n");
}
}
}
您還可以考慮對內部循環使用“增強的循環”語法,這可能會進一步簡化事情。
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