[英]VBA Opening workbook error
我在Access 2010中有一個VB表單,它將打開一個文件對話框以進行excel選擇。 我將文件路徑作為字符串發送到我的變量:directory( directory = strPath
),以打開工作簿並將其內容復制到當前工作簿中。 如果您打算一次使用該工具,則效果很好。 當您導入一個文件,然后導入同一目錄中的另一個文件時,會發生錯誤。
非工作示例:
選定的C:\\ Desktop \\ File1.xls,導入
選定的C:\\ Desktop \\ File2.xls,導入
錯誤:
運行時錯誤“ 1004”:
名為“ Tool.xlsm”的文檔已經打開。 即使文檔位於不同的文件夾中,也無法打開兩個具有相同名稱的文檔。 要打開第二個文檔,請關閉當前打開的文檔,或重命名其中一個文檔。
工作示例(單獨的文件夾):
選定的C:\\ Desktop \\ File1.xls,導入
選定的C:\\ Desktop \\ TestFolder \\ File2.xls,導入
Public Sub CommandButton1_Click()
Dim intChoice As Integer
Dim strPath As String
Application.EnableCancelKey = xlDisabled
'only allow the user to select one file
Application.FileDialog(msoFileDialogOpen).AllowMultiSelect = False
'make the file dialog visible to the user
intChoice = Application.FileDialog(msoFileDialogOpen).Show
'determine what choice the user made
If intChoice <> 0 Then
'get the file path selected by the user
strPath = Application.FileDialog( _
msoFileDialogOpen).SelectedItems(1)
'print the file path to sheet 1
TextBox1 = strPath
End If
End Sub
Public Sub CommandButton2_Click()
Dim directory As String, FileName As String, sheet As Worksheet, total As Integer
Application.ScreenUpdating = False
Application.DisplayAlerts = False
directory = strPath
FileName = Dir(directory & "*.xls")
Do While FileName <> ""
Workbooks.Open (directory & FileName)
For Each sheet In Workbooks(FileName).Worksheets
total = Workbooks("Tool.xlsm").Worksheets.Count
Workbooks(FileName).Worksheets(sheet.name).Copy _
after:=Workbooks("Tool.xlsm").Worksheets(total)
Next sheet
Workbooks(FileName).Close
FileName = Dir()
Loop
Application.ScreenUpdating = True
Application.DisplayAlerts = True
Application.EnableCancelKey = xlDisabled
Application.DisplayAlerts = False
End Sub
在調試模式下,它不喜歡
Workbooks.Open (directory & FileName)
對消除此錯誤的方法有何建議?
首先,在目錄和FileName之間,我假設有一個“ \\”。
其次,只需檢查工作簿是否已打開:
dim wb as workbook
err.clear
on error resume next
set wb = Workbooks (FileName) 'assuming the "\" is not in FileName
if err<>0 or Wb is nothing then 'either one works , you dont need to test both
err.clear
set wb= Workbooks.Open (directory & FileName)
end if
on error goto 0
如果您不使用application.enableevents = false,則打開的Wb將觸發其workbook_open事件!
我想發布工作代碼,也許它將對將來的人有所幫助。 再次感謝那些發表評論的人。
此代碼將打開一個文件對話框,允許用戶選擇1個excel文件,然后將所選文件中的所有圖紙復制到當前工作簿中。
Public Sub CommandButton1_Click()
Dim intChoice As Integer
Application.EnableCancelKey = xlDisabled
'only allow the user to select one file
Application.FileDialog(msoFileDialogOpen).AllowMultiSelect = False
'make the file dialog visible to the user
intChoice = Application.FileDialog(msoFileDialogOpen).Show
'determine what choice the user made
If intChoice <> 0 Then
'get the file path selected by the user
strPath = Application.FileDialog( _
msoFileDialogOpen).SelectedItems(1)
'print the file path to textbox1
TextBox1 = strPath
End If
End Sub
Public Sub CommandButton2_Click()
Dim directory As String, FileName As String, sheet As Worksheet, total As Integer
Dim wb As Workbook
Application.ScreenUpdating = False
Application.DisplayAlerts = False
Err.Clear
On Error Resume Next
Set wb = Workbooks(FileName) 'assuming the "\" is not in FileName
If Err <> 0 Or wb Is Nothing Then 'either one works , you dont need to test both
Err.Clear
Set wb = Workbooks.Open(directory & TextBox1)
End If
On Error GoTo 0
FileName = Dir(directory & TextBox1)
Do While FileName <> ""
Workbooks.Open (directory & TextBox1)
For Each sheet In Workbooks(FileName).Worksheets
total = Workbooks("NAMEOFYOURWORKBOOK.xlsm").Worksheets.Count
Workbooks(FileName).Worksheets(sheet.name).Copy _
after:=Workbooks("NAMEOFYOURWORKBOOK.xlsm").Worksheets(total)
Next sheet
Workbooks(FileName).Close
FileName = Dir()
Loop
Application.ScreenUpdating = True
Application.DisplayAlerts = True
Application.EnableCancelKey = xlDisabled
Application.DisplayAlerts = False
End Sub
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