如何通過Phalcon findFirst找到多個標准？

Question

我正在嘗試從我的視頻數據庫中獲取視頻，選擇基於external_id和language_id （兩個整數）的唯一組合。 我嘗試了下面的代碼，但看起來像findFirst()只能獲得第一個標准

$video = Video::findFirst("language_id=" . $language->id . " and external_id=" . $external->id);

任何人都可以幫助我如何正確使用具有多個標准的findFirst？

Answer 1

嘗試綁定您的參數與連接它們。 更安全，它可能會識別錯誤區域

$video = Video::findFirst(
    [
        'columns'    => '*',
        'conditions' => 'language_id = ?1 AND external_id = ?2',
        'bind'       => [
            1 => $language->id,
            2 => $external->id,
        ]
    ]
);

Answer 2

find（）和findFirst（）方法都接受指定搜索條件的關聯數組：

$robot = Robots::findFirst(array(
    "type = 'virtual'",
    "order" => "name DESC",
    "limit" => 30
));

$robots = Robots::find(array(
    "conditions" => "type = ?1",
    "bind"       => array(1 => "virtual")
));


// What's the first robot in robots table?
$robot = Robots::findFirst();
echo "The robot name is ", $robot->name, "\n";

// What's the first mechanical robot in robots table?
$robot = Robots::findFirst("type = 'mechanical'");
echo "The first mechanical robot name is ", $robot->name, "\n";

// Get first virtual robot ordered by name
$robot = Robots::findFirst(array("type = 'virtual'", "order" => "name"));
echo "The first virtual robot name is ", $robot->name, "\n";

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