[英]extracting numbers from a string in a list via regex
我有一個線性方程式,我正在嘗試用Python
處理它。 該線性方程在列表中。
z=['i=(6040.66194238063)+(51.7296373326464*a)+(41.7319764455748*b)+(-193.993966414084*c)+(-215.670960526368*d)+(-531.841753178744*e)+(5047.1039987166*f)+(3925.37115184923*g)+(77.7712765761365*h)']
我想找到一種方法來構建一個包含所有常量的列表。
import re
m=re.findall('-?[0-9]+\.?[0-9]*', z[0])
會給你一個清單m
:
['6040.66194238063', '51.7296373326464', '41.7319764455748', '-193.993966414084', '-215.670960526368', '-531.841753178744', '5047.1039987166', '3925.37115184923', '77.7712765761365']
如果您希望列表作為浮點數列表,您現在可以執行以下操作:
m = [float(x) for x in m]
如果要在列表中提取常量,則應執行以下操作:
z = ["i=(6040.66194238063)+(51.7296373326464*a)+(41.7319764455748*b)+(-193.993966414084*c)+(-215.670960526368*d)+(-531.841753178744*e)+(5047.1039987166*f)+(3925.37115184923*g)+(77.7712765761365*h)"]
for elem in z:
num = ""
cst = []
for c in elem:
if c.isdigit() or c =='.' or (c == '-' and not len(num)):
num += c
elif len(num):
cst.append(num)
num = ""
print cst
這將輸出:
['6040.66194238063', '51.7296373326464', '41.7319764455748', '193.993966414084', '215.670960526368', '531.841753178744', '5047.1039987166', '3925.37115184923', '77.7712765761365']
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.