mysql order by max匹配字段值

Question

我共有三張桌子

table:Links

id | name | cat_id | weight
1 | test1 | 1 | 5
2 | test2 | 1 | 10
3 | test3 | 1 | 15
4 | test4 | 1 | 2

table:Tags

id | name | link_id 
1 | tag1 | 1 
2 | tag2 | 1 
3 | tag1 | 2 
4 | tag2 | 2 
5 | tag1 | 3 
6 | tag2 | 4 

這里

test1 have tags like: tag1,tag2
test2 have tags like: tag1,tag2
test3 have tags like: tag1
test4 have tags like: tag2

所以我想要最接近的標簽匹配表格測試1

所以結果應該是： test2，test3，test4

取決於標簽匹配和重量

Answer 1

嘗試這個：

SELECT DISTINCT(l.name) AS link 
FROM links l INNER JOIN tags t ON l.id = t.link_id 
AND l.id <> 1 GROUP BY t.link_id ORDER BY COUNT(t.link_id) DESC

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