[英]Fetch data of JSON array on Android
我的數據庫中有一些測試值,我想在android中獲取它們。 這是數據庫中值的以下JSON輸出:
[{"email_address":"rainier_gaari@hotmail.com","comment":"qwehgashdgaskdaweq","date_comment":"2014-06-21","time_comment":"08:28:00","password":"rainier1990"},
{"email_address":"rainier_gaari@hotmail.com","comment":"asfasdasdasd","date_comment":"2104-06-12","time_comment":"09:03:00","password":"rainier1990"}
{"email_address":"rainier_gaari@hotmail.com","comment":"asdsfafd","date_comment":"2014-06-22","time_comment":"04:44:00","password":"rainier1990"}]
但是每次我運行以下代碼: http : //prntscr.com/3vhs5j時 ,它只會為我提供JSON輸出的第一行。http: //prntscr.com/3vi34b
如何顯示android中的所有行(而不是1行)?
如果您在問題中放入一些用於獲取JSON的代碼,這將有所幫助,以使其更易於引用,但是,我看不到循環,這就是為什么它僅獲得第一行的原因。
您可能要參考以下問題: Android / Java中的JSON Array迭代,但基本上使用JSONArray的length
屬性並循環多次。
您可以使用android API提供的JSONObject。 JSONObject有一個稱為getJSONArray()的方法
http://developer.android.com/reference/org/json/JSONObject.html#getJSONArray(java.lang.String)
您的錯誤是您正在使用Object實例化JSONArray。 您應該嘗試這樣:
JSONArray myArray =jsonObject.getJSONArray();
這是我的一個應用程序中的一段代碼,這些代碼很好地檢索了Json數據。
success = jObject.getInt(TAG_SUCCESS);
vehicles = jObject.getJSONArray(Vehicle.TAG_VEHICLES);
if(success == 1) {
// loop through all the vehicles
for(int i = 0; i < vehicles.length(); i++) {
JSONObject obj = vehicles.getJSONObject(i);
// Get each element based on it's tag
String year = obj.getString(Vehicle.TAG_YEAR);
String model = obj.getString(Vehicle.TAG_MODEL);
String brand = obj.getString(Vehicle.TAG_BRAND);
String color = obj.getString(Vehicle.TAG_COLOR);
String license_plate = obj.getString(Vehicle.TAG_LICENSE);
String main_driver = obj.getString(Vehicle.TAG_DRIVER);
String policeNumber = obj.getString(Vehicle.TAG_POLICENUMBER);
String driversLicense = obj.getString(Vehicle.TAG_DRIVER_LICENSE);
String licenseState = obj.getString(Vehicle.TAG_LICENSE_STATE);
String driverBirthday = obj.getString(Vehicle.TAG_BIRTHDAY_MONTH) + "/" +
obj.getString(Vehicle.TAG_BIRTHDAY_DAY) + "/" +
obj.get(Vehicle.TAG_BIRTHDAY_YEAR);
String driverGender = obj.getString(Vehicle.TAG_DRIVER_GENDER);
ListRowGroup group = new ListRowGroup(brand + " " + year + " " + model, brand);
group.children.add(brand + " " + year + " " + model);
group.children.add(policeNumber);
group.children.add(model);
group.children.add(color);
group.children.add(license_plate);
group.children.add(main_driver);
group.children.add(driversLicense + " - " + licenseState);
group.children.add(driverBirthday + " - " + driverGender);
vehiclesGroup.append(i, group);
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.