如果href或src的開頭不是http，https或www，則PHP刪除特定的標記或img標記

Question

如果<src>或<href>在<a>或<img>標記內不以www，http或https開頭，我想從$string_1刪除特定的a和img標記。

例如，通過刪除以下內容，將$string_1轉換為$string_2 ：

<img src="/wp-content/uploads/2014/06/photography-business-2.jpg" alt="photography business growth 1 650x430 6 Simple Ways To Help Grow Your Photography Business" width="650" height="430" class="alignnone size-large wp-image-609513" title="6 Simple Ways To Help Grow Your Photography Business"/>

和

<a href="/photography-business-growth/" rel="nofollow">Read more about Photography Business Growth &gt;</a>

因為src和href標簽不是以http，https或www開頭。

$string_1 = '
<div class="mainpost"><p><img src="/wp-content/uploads/2014/06/photography-business-2.jpg" alt="photography business growth 1 650x430 6 Simple Ways To Help Grow Your Photography Business" width="650" height="430" class="alignnone size-large wp-image-609513" title="6 Simple Ways To Help Grow Your Photography Business"/></p>
<div class="mainpost"><p><img src="http://www.domain.com/wp-content/uploads/2014/06/photography-business-2.jpg" alt="photography business growth 1 650x430 6 Simple Ways To Help Grow Your Photography Business" width="650" height="430" class="alignnone size-large wp-image-609513" title="6 Simple Ways To Help Grow Your Photography Business"/></p>
<p><a href="http://domain.com/photography-business-growth/" rel="nofollow">Read more about Photography Business Growth &gt;</a></p>
<p>Photography Business Growth | With a world wide recession, photographers and small business owners are forced, more than ever, to think creatively, to think differently and outside of the box. With very little or no money to invest in your business, can you move forward? How can you build your brand and make sure to get happier, paying clients through your door?<br/><span id="more-609494"/></p>
<p>If you take good shots it doesn’t mean you’ll gain success and popularity among customers. For those of you who have survived start=up and built successful brands, you may be wondering which step to take next to grow your business beyond its current status. There are numerous possibilities, some of which we’ll outline here. You need to know how to sell yourself well! Everything is quite simple and you can do it yourself.</p>
<p><a href="/photography-business-growth/" rel="nofollow">Read more about Photography Business Growth &gt;</a></p>
';

$string_2= '
<div class="mainpost"><p></p>
<div class="mainpost"><p><img src="http://www.domain.com/wp-content/uploads/2014/06/photography-business-2.jpg" alt="photography business growth 1 650x430 6 Simple Ways To Help Grow Your Photography Business" width="650" height="430" class="alignnone size-large wp-image-609513" title="6 Simple Ways To Help Grow Your Photography Business"/></p>
<p><a href="http://domain.com/photography-business-growth/" rel="nofollow">Read more about Photography Business Growth &gt;</a></p>
<p>Photography Business Growth | With a world wide recession, photographers and small business owners are forced, more than ever, to think creatively, to think differently and outside of the box. With very little or no money to invest in your business, can you move forward? How can you build your brand and make sure to get happier, paying clients through your door?<br/><span id="more-609494"/></p>
<p>If you take good shots it doesn’t mean you’ll gain success and popularity among customers. For those of you who have survived start=up and built successful brands, you may be wondering which step to take next to grow your business beyond its current status. There are numerous possibilities, some of which we’ll outline here. You need to know how to sell yourself well! Everything is quite simple and you can do it yourself.</p>
';

您能幫我解決這個問題嗎？ 謝謝

Answer 1

這是PHP中的第一種方法。 它適用於您的示例數據。 $ string_2中缺少尾部的“ <p> </ p>”。

$string_3 = $string_1;
$pattern = "([^wh]|w[^w]|ww[^w]|h[^t]|ht[^t]|htt[^p])";
$string_3 = preg_replace("/<img src=\"".$pattern."[^>]*>/","",$string_3);
$string_3 = preg_replace("/<a href=\"".$pattern."[^>]*>[^<]*<\/a>/","",$string_3);

Answer 2

我將為此使用DOM解析器。 有了DOM文檔，您可以使用XPath選擇所需的元素。

# Parse the HTML snippet into a DOM document
$doc = new DOMDocument();
$doc->loadHTML($string_1);

# Create an XPath selector
$selector = new DOMXPath($doc);

# Define the XPath query
# The syntax highlighter messed this up. Take it as it is!
$query = <<<EOF
  //a[not(starts-with(@href, "http"))
  and not(starts-with(@href, "www"))]
| //img[not(starts-with(@src, "http"))
  and not(starts-with(@src, "www"))]
EOF;

# Issue the XPath query and remove every resulting node
foreach($selector->query($query) as $node) {
    $node->parentNode->removeChild($node);
}

# Write back the modified `<div>` element into a string
echo $doc->saveHTML(
    $selector->query('//div[@class="mainpost"]')->item(0)
);

Answer 3

一種解決方案是使用Javascript在前端進行此操作。 如果不是這種選擇，則可以查看PHP庫以解析和遍歷DOM，例如http://simplehtmldom.sourceforge.net