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[英]Rendering JSON response string in Java Controller like a Scala Controller
[英]Java JSON Controller to Scala?
我比承認理解JSON文檔更困難。
我想將這個JSON結果轉換為Scala,但我很丟失。 我已經嘗試了很多東西,但我還在學習Scala,所以沒有一個真的值得發帖,因為我甚至不確定它是否有意義。
我在Scala中使用Anorm ORM。 id是Pk[Long]
public static Result checkName(String clubname){
ObjectNode jresult = Json.newObject();
if (Club.clubExists(clubname)) {
jresult.put("error", "Club Name Exists");
return status(409, jresult); // 409 - Conflict
} else {
jresult.put("status", "OK");
return ok(jresult);
}
}
clubExists在模型中:
public static boolean clubExists(String name) {
Club club = find.where().eq("club_name", name).findUnique();
return (club != null);
}
該模型的其余部分非常基本:
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "club_seq")
public Long clubId;
@Column(unique=true, length = 50)
public String clubName;
public Long creator;
public DateTime created;
public Club(String clubName, Long creator) {
this.clubName = clubName;
this.creator = creator;
this.created = new DateTime();
}
public static Finder<Long, Club> find = new Finder<Long, Club>(Long.class, Club.class);
public static Club create(String name, Long creator) {
Club club = new Club(name, creator);
club.save();
return club;
}
public static Result checkName(String clubname){
ObjectNode jresult = Json.newObject();
if (Club.clubExists(clubname)) {
jresult.put("error", "Club Name Exists");
return status(409, jresult); // 409 - Conflict
} else {
jresult.put("status", "OK");
return ok(jresult);
}
}
在Scala中(添加as JSON
以更改MIME類型):
def checkName(clubName:String) = Action {
val jresult = Json.obj()
if (Club.exists(clubName)) {
Conflict(jresult) as JSON
} else {
Ok(jresult) as JSON
}
}
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