簡體   English   中英

按下一個最高編號排序

[英]Order by next highest number

我有一個查詢,該查詢在多個練習中均會影響游戲玩家的排名。 如果他們的分數並列,我需要按每次練習的最高排名來解開。

例如:

     total_points pos1 pos2 pos3
#1   5            1    3    1
#2   7            3    1    3
#3   7            4    1T   2

第二名是當前處於第三名的玩家,因為他在第一名與第二名並列,但他在第二名中排名第二,而第二名則是第二名。 3.(T表示並列,當玩家與另一個並列時應出現在號碼旁邊)

所以理想的結果是

  total_points pos1 pos2 pos3
#1   5            1    3    1
#2   7            4    1T   2
#3   7            3    1    3

我認為排序是通過pos1排序,然后忽略其他位置?

我正在使用的后續查詢是

 SELECT totals.*, scores.*, warriors.*, results.*, positions.* 
       FROM (SELECT results . * , SUM( points ) AS total_points 
           FROM final_results AS results 
           INNER JOIN contest_trainings AS wods ON wods.id = results.wod_id 
           WHERE wods.show_date < NOW( ) 
           GROUP BY contest_id) AS totals, 
       final_results AS scores 
       INNER JOIN (
           SELECT wod1.*, wod1.wod_position AS pos1, wod2.wod_position AS pos2, wod3.wod_position AS pos3 
           FROM final_results AS wod1 
           LEFT OUTER JOIN final_results AS wod2 
           ON wod1.contest_id = wod2.contest_id 
           AND wod2.wod_id > wod1.wod_id 
           LEFT OUTER JOIN final_results AS wod3 
           ON wod2.contest_id = wod3.contest_id 
           AND wod3.wod_id > wod2.wod_id 
           GROUP BY wod1.contest_id) as positions 
        ON positions.contest_id = scores.contest_id 
        INNER JOIN contest AS warriors ON scores.contest_id = warriors.id 
        INNER JOIN contest_results AS results ON scores.contest_id = results.contest_id 
        WHERE totals.contest_id = warriors.id AND results.validated = 1 
        AND warriors.battle = 1 
        AND warriors.category = 1 
        GROUP BY scores.contest_id 
        ORDER BY totals.total_points, 
        positions.pos1, CAST(positions.pos2 AS UNSIGNED), positions.pos3

假設您對第4位感興趣,那么我將嘗試使用以下排序:-

SELECT totals.*, scores.*, warriors.*, results.*, positions.* 
FROM 
(
    SELECT results . * , SUM( points ) AS total_points 
    FROM final_results AS results 
    INNER JOIN contest_trainings AS wods 
    ON wods.id = results.wod_id 
    WHERE wods.show_date < NOW( ) 
    GROUP BY contest_id
) AS totals, 
CROSS JOIN final_results AS scores 
INNER JOIN 
(
    SELECT wod1.*, wod1.wod_position AS pos1, wod2.wod_position AS pos2, wod3.wod_position AS pos3 
    FROM final_results AS wod1 
    LEFT OUTER JOIN final_results AS wod2 
    ON wod1.contest_id = wod2.contest_id 
    AND wod2.wod_id > wod1.wod_id 
    LEFT OUTER JOIN final_results AS wod3 
    ON wod2.contest_id = wod3.contest_id 
    AND wod3.wod_id > wod2.wod_id 
    GROUP BY wod1.contest_id
) as positions 
ON positions.contest_id = scores.contest_id 
INNER JOIN contest AS warriors ON scores.contest_id = warriors.id 
INNER JOIN contest_results AS results ON scores.contest_id = results.contest_id 
WHERE totals.contest_id = warriors.id AND results.validated = 1 
AND warriors.battle = 1 
AND warriors.category = 1 
GROUP BY scores.contest_id 
ORDER BY totals.total_points, 
        IF(positions.pos1 = 1, 1, 0) + IF(positions.pos2 = 1, 1, 0) + IF(positions.pos3 = 1, 1, 0),
        IF(positions.pos1 = 2, 1, 0) + IF(positions.pos2 = 2, 1, 0) + IF(positions.pos3 = 2, 1, 0),
        IF(positions.pos1 = 3, 1, 0) + IF(positions.pos2 = 3, 1, 0) + IF(positions.pos3 = 3, 1, 0),
        IF(positions.pos1 = 4, 1, 0) + IF(positions.pos2 = 4, 1, 0) + IF(positions.pos3 = 4, 1, 0)

可能有可能對此進行改進,但我需要查看更多原始表。

請注意,您的查詢似乎可能有一些不確定的結果。 例如,您的第一個子查詢執行GROUP BY race_id,但返回final_results表中的所有內容。 不確定所有這些列是否都取決於race_id的單個值(但不能確定,因為我不知道final_results和race_trainings的布局方式)。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM