CoffeeScript-如何在類中檢索靜態數組屬性

Question

我剛開始學習CoffeeScript，我想知道從子實例中檢索類中的靜態屬性的最佳實踐是什么。

class Mutant
    MutantArray: []

    constructor: (@name, @strength = 1, @agility = 1) ->
        @MutantArray.push(@name)

    attack: (opponent) ->
        if opponent in @MutantArray then console.log @name + " is attacking " + opponent else console.log "No Mutant by the name of '" + opponent + "' found."


    @getMutants: () ->
        # IS THIS RIGHT?
        console.log @.prototype.MutantArray

Wolverine = new Mutant("Wolverine", 1, 2)
Rogue = new Mutant("Rogue", 5, 6)

Rogue.attack("Wolverine")

Mutant.getMutants()

我希望我的getMutants（）方法是靜態的（無需實例化），並返回已實例化的Mutant名稱列表。 @ .prototype.MutantArray似乎可以正常工作，但是有更好的方法嗎？ 我嘗試了@MutantArray，但是沒有用。

謝謝！

Answer 1

我認為您應該將MutantArray定義為靜態字段。 然后，從非靜態方法中，您應該通過類對其進行引用，而從靜態方法中，則應通過@訪問它。 像這樣：

class Mutant
    @MutantArray: []

    constructor: (@name, @strength = 1, @agility = 1) ->
         Mutant.MutantArray.push(@name)

    attack: (opponent) ->
        if opponent in Mutant.MutantArray then console.log @name + " is attacking " + opponent else console.log "No Mutant by the name of '" + opponent + "' found."


    @getMutants: () ->
        # IS THIS RIGHT?
        console.log @MutantArray

Answer 2

我認為是這樣的：

class Mutant
    MutantArray: []

    constructor: (@name, @strength = 1, @agility = 1) ->
        @MutantArray.push(@name)

    attack: (opponent) ->
        if opponent in @MutantArray then console.log @name + " is attacking " + opponent else console.log "No Mutant by the name of '" + opponent + "' found."


    getMutants: () ->
        # IS THIS RIGHT?
        console.log @.MutantArray

Wolverine = new Mutant("Wolverine", 1, 2)
Rogue = new Mutant("Rogue", 5, 6)

Rogue.attack("Wolverine")

Mutant.getMutants()

getMutants必須是原型方法，然后使用@ .getMutants檢索數組值