[英]What will be the equivalent to following curl command in java
我需要將以下curl命令轉換為java命令。
$curl_handle = curl_init ();
curl_setopt ($curl_handle, CURLOPT_URL,$url);`enter code here`
curl_setopt ($curl_handle, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt ($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt ($curl_handle, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt ($curl_handle, CURLOPT_POST, 1);
curl_setopt ($curl_handle, CURLOPT_POSTFIELDS, $postfields);
//echo $postfields;
$curl_result = curl_exec ($curl_handle) or die ("There has been a CURL_EXEC error");
Http(s)UrlConnection
可能是您的首選武器:
public String sendData() throws IOException {
// curl_init and url
URL url = new URL("http://some.host.com/somewhere/to/");
HttpURLConnection con = (HttpURLConnection) url.openConnection();
// CURLOPT_POST
con.setRequestMethod("POST");
// CURLOPT_FOLLOWLOCATION
con.setInstanceFollowRedirects(true);
String postData = "my_data_for_posting";
con.setRequestProperty("Content-length", String.valueOf(postData.length()));
con.setDoOutput(true);
con.setDoInput(true);
DataOutputStream output = new DataOutputStream(con.getOutputStream());
output.writeBytes(postData);
output.close();
// "Post data send ... waiting for reply");
int code = con.getResponseCode(); // 200 = HTTP_OK
System.out.println("Response (Code):" + code);
System.out.println("Response (Message):" + con.getResponseMessage());
// read the response
DataInputStream input = new DataInputStream(con.getInputStream());
int c;
StringBuilder resultBuf = new StringBuilder();
while ( (c = input.read()) != -1) {
resultBuf.append((char) c);
}
input.close();
return resultBuf.toString();
}
我不太確定HTTPS_VERIFYPEER-thing
,但這可能會給你一個起點。
看看java.net.URL和java.net.URLConnection庫。
URL url = new URL("yourUrl.com");
然后使用InputStreamReader和BufferedReader。
更多信息在Oracles示例中: http : //docs.oracle.com/javase/tutorial/networking/urls/readingWriting.html
這也可能有所幫助: 如何在Java中使用cURL?
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