獲取具有子元素的數組元素，而無需在PHP中重復

Question

我有些猶豫，在這里走來走去，我已經傳遞了一個帶有子元素的數組（可以這么說），我需要三個隨機值，但是這些都是隨機獲得的。

數組如下：

Array
    (
        [0] => Array
            (
                [uid] => 1
                [ticket_code] => 0oreb8yo
            )

        [1] => Array
            (
                [uid] => 1
                [ticket_code] => 2oeii8hm
            )

        [2] => Array
            (
                [uid] => 1
                [ticket_code] => m0dwtjiw
            )

        [3] => Array
            (
                [uid] => 1
                [ticket_code] => q6c7cymb
            )

        [4] => Array
            (
                [uid] => 1
                [ticket_code] => zyqhm5bj
            )

        [5] => Array
            (
                [uid] => 1
                [ticket_code] => amdqzjpi
            )

        [6] => Array
            (
                [uid] => 2
                [ticket_code] => tzql7l42
            )

        [7] => Array
            (
                [uid] => 2
                [ticket_code] => gap0r6vf
            )

        [8] => Array
            (
                [uid] => 2
                [ticket_code] => ypqum5yz
            )

        [9] => Array
            (
                [uid] => 4
                [ticket_code] => smupluac
            )

        [10] => Array
            (
                [uid] => 4
                [ticket_code] => 9d8jsha7
            )

        [11] => Array
            (
                [uid] => 5
                [ticket_code] => 6hdnja42
            )

    )

我需要您獲得3個“ ticket_code”，但無權重復“ uid”。

我一直在嘗試如下，但也重復了“ uid”。

$ticketsWinners = array();
  for ($i=0; $i < 3; $i++) {
    $aux = array_rand($allTickets);
    $aux2 = $allTickets[$aux]['uid'];

    $ticketsWinners[] = array(
      'uid' => $aux2,
      'ticket_code' => $allTickets[$aux]['ticket_code']
    );
  }

有沒有辦法重復做？

如果有人知道我們會先謝謝您^^

Answer 1

嘗試類似：

$ticketsWinners = array();
while (sizeof($ticketsWinners) < 3) {
    $aux = array_rand($allTickets);
    // array_rand return array of keys so you need first value only
    $uid = $allTickets[$aux[0]]['uid']

    // add uid as a key so ass not tot check all $allTickets values
    if (!isset($ticketsWinners[$uid]))
        $ticketsWinners[$uid] = $allTickets[$aux[0]]; 
}
// if you need $allTickets back to numeric keys [0, 1, 2]
$allTickets = array_values($allTickets);

如果您擔心無限循環（可能確實發生），請嘗試以下操作：

$ticketsWinners = array();
// shuffle array before checking
shuffle($allTickets);
foreach ($allTickets as $tick_data) {
    $uid = $tick_data['uid'];

    if (!isset($ticketsWinners[$uid]))
        $ticketsWinners[$uid] = $tick_data;

    if (sizeof($ticketsWinners) == 3)
        break;
}

在最壞的情況下，您檢查$allTickets數組並獲得大小為<= 3獲勝者。

Answer 2

嘗試這個：

$ticketsWinners = array();
$ticketUid = array();
for ($i=0; $i < 3; $i++) {
    $aux = array_rand($allTickets);
    $aux2 = $allTickets[$aux]['uid'];

    if(! in_array($aux2, $ticketUid)) {
        $ticketUid[$i] = $aux2;

        $ticketsWinners[] = array(
          'uid' => $aux2,
          'ticket_code' => $allTickets[$aux]['ticket_code']
        );
    } else {
        $i--;
    }
}

Answer 3

這種結構會更好（機票號碼唯一的額外好處）

$tickets = Array
    (
    '0oreb8yo' => 1,              
    '2oeii8hm' => 1,
    'm0dwtjiw' => 1,
    'q6c7cymb' => 1,
     'zyqhm5bj' => 1,
    'amdqzjpi' => 1,
    'tzql7l42' => 2,
    'gap0r6vf' => 2,
    'ypqum5yz' => 2,
    'smupluac' => 3,
    '9d8jsha7' => 4,
    '6hdnja42' => 5,
    );

        $winners = array();
        $picks = 3;
        for($i = 0; $i < $picks; $i++){
if(count($tickets) == 0 ){
break; //or error -- shouldn't need this unless picks exceed uids
}
            $ticket = array_rand($tickets);
            $winner = $tickets[$ticket];
            $winners[] = $winner;
            $tickets = array_filter($tickets, function($item) use ($winner){
                return $winner != $item;
            });
        }

        echo '<pre>';
        var_export($winners);

輸出

array (
  0 => 2,
  1 => 1,
  2 => 4,
)

array (
  0 => 2,
  1 => 1,
  2 => 3,
)

array (
  0 => 1,
  1 => 3,
  2 => 2,
)

與while選項不同，這將通過減少uid的票證數組來減少for循環的每個循環操作。 這也是確保您不總是抽出用戶票證的唯一方法，如果用戶1購買了90％的票證，您將有90％的時間向他循環，無論如何，您都必須減少票證陣列如果獲勝者只能贏一次，則由獲勝者決定。 本質上，當每個uid贏時，您將從列表中刪除它們。 您還可以確保每張彩票都有相同的中獎機會（以及array_rand是隨機的）-它們都有平等的立足點。

loop1之后的票證數組減少

array (
  'tzql7l42' => 2,
  'gap0r6vf' => 2,
  'ypqum5yz' => 2,
  'smupluac' => 3,
  '9d8jsha7' => 4,
  '6hdnja42' => 5,
)

在loop2之后

array (
  'smupluac' => 3,
  '9d8jsha7' => 4,
  '6hdnja42' => 5,
)

在loop3之后

array (
  'smupluac' => 3,
  '6hdnja42' => 5,
)

獲獎者

array (
  0 => 1,
  1 => 2,
  2 => 4,
)

返回uid和中票變更

$winners[] = $winner;

至

$winners[$ticket] = $tickets[$ticket];

現在贏家將會像輸入數組一樣

ticketnumber => uid

票證是鍵（即票證），獲勝者是值（即uid）