PHP每隔10個mysql結果添加html中斷

Question

我的代碼有問題。 我想要達到的目標：

我有一個名為“比賽”的數據庫表，其中包含有關足球比賽器材的信息。 現在我在這張表中大約有100個匹配項，但是很快就會超過500個，所以為了不讓觀眾震驚，我希望我的代碼執行換行符（或者可能是一個新的表格行，那現在不重要了，只是每10個結果后顯示一些HTML標簽）（因為每周有10個匹配項）

這是我的PHP代碼：

$sql = "SELECT * FROM matches ORDER BY matchid ASC";
$query = mysqli_query($Connection, $sql) or die (mysqli_error($sql));
$fixtures='';
while($row = mysqli_fetch_array( $query )) { 
    $fixturetime = $row["time"];
    $fixturetime2 = $row["time"];
    $fixtureid = $row["matchid"];
    $fixtureround = $row["round"];
    $hometeamid = $row["hometeamid"];
    $awayteamid = $row["awayteamid"];
    $fixturetime = strtotime( $fixturetime );
    $fixturetime = date( 'd.m.Y', $fixturetime );
    $fixturetime2 = strtotime( $fixturetime2 );
    $fixturetime2 = date( 'H:i', $fixturetime2 );

    $fixtures.='<tr><td><strong>' .$hometeamname. '</strong> v. <strong>' .$awayteamname. '</strong></td><td>' .$fixturetime. '</td><td>' .$fixturetime2. '</td><td style="text-align: right;">' .$fixtureid. '</td><td>' .$i. '</td></tr>';
}

這是HTML輸出：

<table>
    <?php echo $fixtures; ?>
</table>

我嘗試了一些在stackoverflow上顯示的方法，但無法將其正確實現到我的解決方案中。 因為我對PHP有點陌生，所以我要求特定的解決方案。

謝謝。

Answer 1

嘗試這個 ;）

<?php

$sql = "SELECT * FROM matches ORDER BY matchid ASC";
$query = mysqli_query($Connection, $sql) or die (mysqli_error($sql));
$fixtures = '';
$i = 1;

while($row = mysqli_fetch_array($query)) {
    $fixturetime = $row["time"];
    $fixturetime2 = $row["time"];
    $fixtureid = $row["matchid"];
    $fixtureround = $row["round"];
    $hometeamid = $row["hometeamid"];
    $awayteamid = $row["awayteamid"];
    $fixturetime = strtotime($fixturetime);
    $fixturetime = date('d.m.Y', $fixturetime);
    $fixturetime2 = strtotime($fixturetime2);
    $fixturetime2 = date('H:i', $fixturetime2);

    $fixtures .= '<tr><td><strong>' . $hometeamname . '</strong> v. <strong>' . $awayteamname . '</strong></td><td>' . $fixturetime . '</td><td>' . $fixturetime2 . '</td><td style="text-align: right;">' . $fixtureid . '</td><td>' . $i . '</td></tr>';

    if(!($i % 10)){
        $fixtures .= '<!-- break -->';
    }

    $i++;
}

Answer 2

我建議使用mod或％符號，這將返回除法的余數（因此，每10行n / 10的余數將為0）。

所以你想要一個櫃台

$count = 1;
while( $row = ..... ){
    if( $count % 10 == 0 ){
     //do line break;
   }


   ++$count;
}

php關於mod的文檔http://www.php.net/manual/zh/internals2.opcodes.mod.php

您可能需要對此稍作練習，但這是基礎。

Answer 3

我建議我能想到的最簡單的事情。

$sql = "SELECT * FROM matches ORDER BY matchid ASC";
$query = mysqli_query($Connection, $sql) or die (mysqli_error($sql));
$fixtures='';
$counter = 0;
while($row = mysqli_fetch_array( $query )) { 
$counter++;
$fixturetime = $row["time"];
$fixturetime2 = $row["time"];
$fixtureid = $row["matchid"];
$fixtureround = $row["round"];
$hometeamid = $row["hometeamid"];
$awayteamid = $row["awayteamid"];
$fixturetime = strtotime( $fixturetime );
$fixturetime = date( 'd.m.Y', $fixturetime );
$fixturetime2 = strtotime( $fixturetime2 );
$fixturetime2 = date( 'H:i', $fixturetime2 );

$fixtures.='<tr><td><strong>' .$hometeamname. '</strong> v. <strong>' .$awayteamname. '</strong></td><td>' .$fixturetime. '</td><td>' .$fixturetime2. '</td><td style="text-align: right;">' .$fixtureid. '</td><td>' .$i. '</td></tr>';

if (($counter % 10) == 0){ $fixtures .= '<br>'; }
}

每次while迭代時，這將為計數器加1。 如果對$ counter進行10位檢查后，if語句將檢查是否還有余數。如果有余數，它將繼續運行而不會出現換行符。 如果沒有余數，即為10的倍數，則會附加一個
到最后。

希望這就是你想要的！

Answer 4

您將需要計算每一行。 使用從0開始的新變量$i ，該變量將在每個循環中增加一。 然后檢查該變量是否大於10。如果是，請在$fixtures字符串中添加更多html，以創建“空白”行。

如果發現空白行，請將$i變量重置為0

$sql = "SELECT * FROM matches ORDER BY matchid ASC";
$query = mysqli_query($Connection, $sql) or die (mysqli_error($sql));
$fixtures='';
$i = 0; // <-- New variable

while($row = mysqli_fetch_array( $query )) { 

    $fixturetime = $row["time"];
    $fixturetime2 = $row["time"];
    $fixtureid = $row["matchid"];
    $fixtureround = $row["round"];
    $hometeamid = $row["hometeamid"];
    $awayteamid = $row["awayteamid"];
    $fixturetime = strtotime( $fixturetime );
    $fixturetime = date( 'd.m.Y', $fixturetime );
    $fixturetime2 = strtotime( $fixturetime2 );
    $fixturetime2 = date( 'H:i', $fixturetime2 );

    $fixtures.='<tr><td><strong>' .$hometeamname. '</strong> v. <strong>' .$awayteamname. '</strong></td><td>' .$fixturetime. '</td><td>' .$fixturetime2. '</td><td style="text-align: right;">' .$fixtureid. '</td><td>' .$i. '</td></tr>';

    $i ++; // <-- add one

    if ($i > 10) { // <-- If larger than 10 then do this statement

        $fixtures.='<tr><td colspan=4>BREAK</td></tr>';
        $i = 0; // <-- Oh and reset $i
    }

}

Answer 5

我將查找將OFFSET與LIMIT子句一起使用的分頁解決方案。 除此之外，您實際上可以將結果存儲在10個一組中，然后在遍歷各組時應用輸出邏輯：

$sql = "SELECT * FROM matches ORDER BY matchid ASC";
$query = mysqli_query($Connection, $sql) or die (mysqli_error($sql));
$fixtures = array(); // Each element will be an array of fixtures
$fixturesPerGroup = 10; // How many fixtures per group
$fixtureCount = 0; // Counter during the while loop iterating
$fixtureGroup = 0; // Which group to put the fixtures into
while($row = mysqli_fetch_array( $query )) { 
    $fixturetime = $row["time"];
    $fixturetime2 = $row["time"];
    $fixtureid = $row["matchid"];
    $fixtureround = $row["round"];
    $hometeamid = $row["hometeamid"];
    $awayteamid = $row["awayteamid"];
    $fixturetime = strtotime( $fixturetime );
    $fixturetime = date( 'd.m.Y', $fixturetime );
    $fixturetime2 = strtotime( $fixturetime2 );
    $fixturetime2 = date( 'H:i', $fixturetime2 );

    $fixtures[$fixtureGroup][] ='<tr><td><strong>' .$hometeamname. '</strong> v. <strong>' .$awayteamname. '</strong></td><td>' .$fixturetime. '</td><td>' .$fixturetime2. '</td><td style="text-align: right;">' .$fixtureid. '</td><td>' .$i. '</td></tr>';

    $fixtureCount++;
    // Once we reach the fixturesPerGroup count, go to the next group
    if (($fixtureCount % $fixturesPerGroup) == 0) {
        $fixtureGroup++;
    }
}

然后，您可以遍歷各組：

<table>
<?php 
foreach ($fixtures as $fixturesInGroup) {
    // Do logic here for displaying each group
    echo implode('<br />', $fixturesInGroup);
}
?>
</table>