[英]AFNetworking: Get JSON Value From Http Response
我主要是一名Android開發人員,並且是IOS的新手。 我正在使用AFNetworking 1.0,因為我正在使用現有資源,並且正在發送標准的http Post請求並返回數據,如下所示:
//Sending the post request and getting the result
AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:[NSURL URLWithString:@"http://testsite.org/mobile_app"]];
[httpClient setParameterEncoding:AFFormURLParameterEncoding];
NSMutableURLRequest *request = [httpClient requestWithMethod:@"POST"
path:@"http://testsite.org/mobile_app/studentregister.php"
parameters:@{@"username":username, @"displayname":displayname, @"password":password, @"passwordc":passwordc, @"email":email, @"teacherCode":teacherCode}];
AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc] initWithRequest:request];
[httpClient registerHTTPOperationClass:[AFHTTPRequestOperation class]];
[operation setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation, id responseObject) {
// Print the response body in text
NSLog(@"Response: %@", [[NSString alloc] initWithData:responseObject encoding:NSUTF8StringEncoding]);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
[operation start];
根據burp西裝,響應中應包含如下所示的JSON數據:
{"userCharLimit":"Your username must be between 5 and 25 characters in length"}
{"displaynameCharLim":"Your displayname must be between 5 and 25 characters in length"}
{"passLimit":"Your password must be between 8 and 50 characters in length"}
{"emailInvalid":"Not a valid email address"}
{"teacherCodeLength":"Your teacher code is not 5 to 12 characters"}.
如何獲取這些JSON值? 我已經看過很多AFNetworking 2.0 JSON示例和發送JSON Post請求,但是我似乎可以在1.0版中找到很多東西,更不用說從標准post請求中獲取值了。 有什么想法或資源嗎?
您需要做的就是更改代碼以注冊AFJSONRequestOperation而不是AFHTTPRequestOperation。
[httpClient registerHTTPOperationClass:[AFJSONRequestOperation class]];
然后,您可以在AFHTTPClent上使用此方法來創建實際上為AFJSONRequestOperation類型的操作。
AFHTTPRequestOperation *operation = [httpClient HTTPRequestOperationWithRequest:request success:nil failure:nil];
[httpClient enqueueOperation:operation];
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