[英]Symfony2 array of forms?
是否可以創建和渲染我知道的關於集合的表單,但它們並不真正符合我的想法?
我想要的是這樣的
$data=$em->findAll();
$Forms=$this->createForm(new SomeType,$data);
return $this->render(someView,array("Forms"=>$Forms->createView()));
{% for Form in Forms %}
{{ form(Form)}}
{% endfor %}
只需在數組中創建表單:
$data = $em->findAll();
for ($i = 0; $i < $n; $i++) {
$forms[] = $this->container
->get('form.factory')
->createNamedBuilder('form_'.$i, new SomeType, $data)
->getForm()
->createView();
}
return $this->render(someView, array("forms" => $forms));
正如edlouth所提到的,您可以創建單獨命名的每個表單。 我更新了我的代碼。
在數組中創建表單,但為每個表單指定一個唯一的名稱。 我把它改成了formbuilder,這可能不適合你,但希望類似的東西能起作用。 我也不確定是否要使用new SomeType
而不是'form',請參閱http://api.symfony.com/2.4/Symfony/Component/Form/FormFactory.html#method_createNamedBuilder 。
$data = $em->findAll();
for ($i = 0; $i < $n; $i++) {
$forms[] = $this->container
->get('form.factory')
->createNamedBuilder('form_'.$i, new SomeType, $data)
->getForm()
->createView();
}
return $this->render(someView, array("forms" => $forms));
Symfony3:
$datas = $em->findAll();
foreach ($datas as $key=>$data)
{
$form_name = "form_".$key;
$form = $this->get('form.factory')->createNamed(
$form_name,
SomeType::class,
$data
);
$views[] = $form->createView();
}
return $this->render(someView, ["forms" => $views]);
那個行動 :
$forms = [];
foreach ($articles as $article) {
$forms[$article->getId()] = $this->get('form.factory')->createNamed(
'article_'.$article->getId(), // unique form name
ArticleType::class,
$article
);
$forms[$article->getId()]->handleRequest($request);
if ($forms[$article->getId()]->isValid()) {
// do what you want with $forms[$article->getId()]->getData()
// ...
}
}
還有一種更好的渲染方式:
return $this->render('some_view.html.twig', [
'forms' => array_map(function ($form) {
return $form->createView();
}, $forms),
]);
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