[英]passing struct as argument in function
我想在我的函數中將結構作為參數傳遞,但是在傳遞結構時遇到一些問題。
沒有功能的代碼是:
#include <stdio.h>
#include <stdlib.h>
struct student{
char name[100];
char roll[100];
int marks[5];
}a[3];
typedef struct student s;
void stuwise(s *a);
void subwise(s *a);
int i;
int j;
int m;
int main(int argc, char const *argv[])
{
for(i=0;i<3;i++)
{
printf("Enter Student %d Name \n",i+1);
fgets(a[i].name,100,stdin);
printf("Enter Student %d Roll Number \n",i+1);
fgets(a[i].roll,10,stdin);
for(m=0;m<5;m++)
{
printf("Enter Student %d Marks %d\n",i+1,m+1);
scanf("%d",&(a[i].marks[m]));
getchar();
}
}
printf("Student wise list :\n");
for(j=0;j<3;j++)
{
for(m=0;m<5;m++)
{
printf("Student %d Marks %d ",j+1,m+1);
printf("%d ",(a[j].marks[m]));
printf("\n");
}
printf("\n");
}
printf("Subject wise list :\n");
for(m=0;m<5;m++)
{
for(j=0;j<3;j++)
{
printf("Student %d Marks %d ",j+1,m+1);
printf("%d ",(a[j].marks[m]));
printf("\n");
}
printf("\n");
}
return 0;
}
我嘗試使用功能:
#include <stdio.h>
#include <stdlib.h>
struct student{
char name[100];
char roll[100];
int marks[5];
}a[3];
typedef struct student s;
void stuwise(s *a);
void subwise(s *a);
int i;
int j;
int m;
int main(int argc, char const *argv[])
{
for(i=0;i<3;i++)
{
printf("Enter Student %d Name \n",i+1);
fgets(a[i].name,100,stdin);
printf("Enter Student %d Roll Number \n",i+1);
fgets(a[i].roll,10,stdin);
for(m=0;m<5;m++)
{
printf("Enter Student %d Marks %d\n",i+1,m+1);
scanf("%d",&(a[i].marks[m]));
getchar();
}
}
stuwise(s a);
return 0;
}
void stuwise(s *a)
{
printf("Subject wise list :\n");
for(m=0;m<5;m++)
{
for(j=0;j<3;j++)
{
printf("Student %d Marks %d ",j+1,m+1);
printf("%d ",(a[j].marks[m]));
printf("\n");
}
printf("\n");
}
}
void subwise(s *a)
{
printf("Student wise list :\n");
for(j=0;j<3;j++)
{
for(m=0;m<5;m++)
{
printf("Student %d Marks %d ",j+1,m+1);
printf("%d ",(a[j].marks[m]));
printf("\n");
}
printf("\n");
}
}
它無法正常工作,因為我收到一個錯誤“ s之前的預期表達式”
stuwise(sa);
是調用函數的錯誤方法。 您不必指定變量的類型,因為您已經在函數定義中說明了這一點。
用。。。來代替:
stuwise(a);
要么
stuwise(&a[0]);
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