[英]django save file into folder
我想將文件保存到單獨的文件夾中,但是文件夾名稱我將從我不知道的表格中獲取。 但是我現在有可以保存到user_(某物)的工作表。
誰能告訴我如何定義模型類和視圖以獲取文件夾名稱和我上傳的文件自動保存到單獨的文件夾中。
models.py
def content_file_name(instance, filename):
return "user_{id}/{file}".format(id=instance, file=filename)
class Audio(models.Model):
audiofile = models.FileField(upload_to=content_file_name)
views.py
def saved_file(request):
# Handle file upload
if request.method == 'POST':
form = AudioForm(request.POST, request.FILES)
if form.is_valid():
newaudio = AudioForm()
newaudio = Audio(audiofile = request.FILES['audiofile'])
newaudio.save()
#This is for redirect to the file save_list after post
return HttpResponseRedirect(reverse('app.views.saved_file'))
else:
form = AudioForm()
# Load documents for the save_list page
showfiles = Audio.objects.all()
return render_to_response(
'audio/file_upload.html',
{'showfiles': showfiles, 'form': form},
context_instance=RequestContext(request)
)
您可以將文件夾名稱作為模型的一部分,然后相應地修改content_file_name
函數嗎?
def content_file_name(instance, filename):
return "user_{id}/{folder}/{file}".format(id=instance, folder=instance.folder_name, file=filename)
class Audio(models.Model):
audiofile = models.FileField(upload_to=content_file_name)
folder_name = models.CharField(max_length=1000)
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