在php中編碼網址

Question

我有字符串url變量；

$url ="http://carkva-gazeta.org/римско-католическая-церковь/";

我需要將$ url轉換為：

"http://carkva-gazeta.org/%d1%80%d0%b8%d0%bc%d1%81%d0%ba%d0%be-%d0%ba%d0%b0%d1%82%d0%be%d0%bb%d0%b8%d1%87%d0%b5%d1%81%d0%ba%d0%b0%d1%8f-%d1%86%d0%b5%d1%80%d0%ba%d0%be%d0%b2%d1%8c/"

我試過了： rawurlencode($url); 和urlencode($url); 但是結果是：

http%3A%2F%2Fcarkva-gazeta.org%2F%D1%80%D0%B8%D0%BC%D1%81%D0%BA%D0%BE-%D0%BA%D0%B0%D1%82%D0%BE%D0%BB%D0%B8%D1%87%D0%B5%D1%81%D0%BA%D0%B0%D1%8F-%D1%86%D0%B5%D1%80%D0%BA%D0%BE%D0%B2%D1%8C%2F

Answer 1

$url = "http://carkva-gazeta.org/";
$url .= urlencode("римско-католическая-церковь");

echo $url;

這樣嗎

Answer 2

也許那是最好的解決方案：

$url ="http://carkva-gazeta.org/римско-католическая-церковь/";

$x = parse_url($url);

echo $x['scheme'].'://'.$x['host'].strtolower(str_replace('%2F','/',urlencode($x['path'])));

我也用strtolower將它設置為小寫

Answer 3

假設您正在自動/動態獲取URL字符串，並且它不是固定字符串，您可以在編寫代碼時簡單地對其進行拆分，那么您將需要這樣的內容

$url = "http://carkva-gazeta.org/римско-католическая-церковь/";

// in case it is https, we don't want to hardcode http
$scheme = parse_url($url, PHP_URL_SCHEME);
$host = parse_url($url, PHP_URL_HOST);
// do not encode the first '/' or the last '/'
$encodedPath = strtolower(urlencode(substr(parse_url($url, PHP_URL_PATH), 1, -1)));

$encodedUrl = $scheme . "://" . $host . "/" . $encodedPath . "/";

演示