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帶動態pl / sql的where子句中的字符串變量

[英]string variable in where clause with dynamic pl/sql

我有以下代碼:

declare
  instr varchar2(20);
  num_no number;

begin 
    select AR_ID, ID
    into instr, num_no
    from quelle_match
    where ID = 1;

      execute immediate 'CREATE or replace VIEW interm2 AS
      SELECT AR_ID, kurs,
        ((TO_CHAR(to_date(di.kursdatum,''dd.mm.yyyy''),''YYYYMMDD''))+    (TO_CHAR(to_date(di.verfall,''dd.mm.yyyy''),''YYYYMMDD''))) AS dumdate
      FROM daten_import di 
      where di.AR_ID = '||instr||'';      

  -- where di.AR_ID = ''GXIndex''';

end ;

我收到錯誤b / c instr無效。 當我用實際的字符串GXIndex替換變量時,代碼起作用。 它也可以使用數字作為變量,但不能使用字符串。 這是為什么?

這個:

  execute immediate 'CREATE or replace VIEW interm2 AS
  SELECT AR_ID, kurs,
    ((TO_CHAR(to_date(di.kursdatum,''dd.mm.yyyy''),''YYYYMMDD''))+    (TO_CHAR(to_date(di.verfall,''dd.mm.yyyy''),''YYYYMMDD''))) AS dumdate
  FROM daten_import di 
  where di.AR_ID = '||instr||''; 

應該:

  execute immediate 'CREATE or replace VIEW interm2 AS
  SELECT AR_ID, kurs,
    ((TO_CHAR(to_date(di.kursdatum,''dd.mm.yyyy''),''YYYYMMDD''))+    (TO_CHAR(to_date(di.verfall,''dd.mm.yyyy''),''YYYYMMDD''))) AS dumdate
  FROM daten_import di 
  where di.AR_ID = '||instr; 

如果instr是一個整數,我認為是。

您連接instr的方式存在問題。 為了清楚起見,讓我簡化您的問題:

EXECUTE IMMEDIATE
  'CREATE OR REPLACE VIEW interm2 AS
   SELECT ar_id FROM daten_import di
   WHERE di.ar_id = ' || instr;

instr是一個字符串。 您需要在其周圍加上引號。

EXECUTE IMMEDIATE
  'CREATE OR REPLACE VIEW interm2 AS
   SELECT ar_id FROM daten_import di
   WHERE di.ar_id = ''' || instr || '''';
--                  ^^               ^^
--                  ||               ||
--                  -- escaped quotes--

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