[英]What is the best way to extract the numbers out of this text
P1W2DT6H21M32S
想知道從此處提取數字的最佳方法。
W = Weeks
D = Days
H = Hours
M = Minutes
S = Seconds
這樣的事情僅適用於M和S,似乎我做的不對。
var time = "PT44M7S";
var minutes = time.substring(2, time.indexOf("M"));
var seconds = time.split("M")[1].substring(0, time.split("M")[1].indexOf("S"));
var timePeriod = {};
var str = 'P1W2DT6H21M32S';
var re = /(\d+)([WDHMS])/g;
while (result = re.exec(str)) {
timePeriod[result[2]] = parseInt(result[1], 10);
}
console.log(timePeriod);
應該產生:
{ W: 1, D: 2, H: 6, M: 21, S: 32 }
您可以拆分字母,盡管會在數組中得到前導和尾隨空格:
'P1W2DT6H21M32S'.split(/[AZ]/)
使用正則表達式,您可以“可選地”捕獲每個組,然后根據需要調用它們:
(?:(\d+)W)?(?:(\d+)D?)?(?:(\d+)H)?(?:(\d+)M)?(?:(\d+)S)?
var re = /(?:(\d+)W)?(?:(\d+)D?)?(?:(\d+)H)?(?:(\d+)M)?(?:(\d+)S)?/gm;
var str = 'P1W2DT6H21M32S\nPT44M7S\n';
var subst = 'Week: $1\nDay: $2\nHour: $3\nMinute: $4\nSecond: $5\n';
var result = str.replace(re, subst);
如何將末端的非數字部分丟掉然后拆分其余的非數字塊呢?
var justNumbers = "P1W2DT6H21M32S".replace(/^\D|\D$/g, "").split(/\D+/);
那應該給你一個干凈的數字數組。
如果要將結果數組值存儲在更容易理解的對象中,則可以添加以下內容:
var keys = ["weeks", "days", "hours", "minutes", "seconds"];
var time = {};
for (var k = 0; k < keys.length; k++) {
time[keys[k]] = justNumbers[k];
}
JSFiddle: http : //jsfiddle.net/briansexton/AXh7F/
考慮這樣的正則表達式:
/P(?:(\d+)W)?(?:(\d+)D)?T(?:(\d+)H)?(?:(\d+)M)?(?:(\d+)S)?/
然后,這些值將在組1 = W,2 = D,3 = H,4 = M,5 = S中。
這種與普通拆分相比的優勢在於,如果省略了任何字段,只要提供的字段保持順序,它仍然可以正常工作。
我不知道為什么會有這兩個字母:P和T。但是由於它們在那里,您需要刪除它們。 因此,您可以拆分文本,然后從剛獲得的數組中刪除空字符串:
var time = 'P1W2DT6H21M32S';
time = time.split(/[A-Z]/);
time = time.join(',').replace(/,,/g, ',').substr(1).slice(0, -1).split(',');
> ["1", "2", "6", "21", "32"]
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