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[英]TypeError: string indices must be integers, not str in python
[英]typeerror string indices must be integers not str python
我定義了一個具有一個參數“ students”的函數get_class_average()
。 students
是3個學生的列表:lloyd,alice,tyler,它們是間接詞典。 get_average()
是一個計算平均值的函數,它可以正常工作。 當我嘗試調用函數get_class_average()
出現錯誤:
typeerror string indices must be integers not str
我的密碼
lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}
# Add your function below!
from math import *
def average(numbers):
total = sum(numbers)
total = float(total)
ans = total / len(numbers)
return ans
num = [1,2,4,5,6]
a = average(num)
print a
def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
sum = (0.1*homework) + (0.3 * quizzes) + (0.6 * tests)
return sum
student = [lloyd, alice, tyler]
for key in student:
a = get_average(key)
print a
def get_letter_grade(score):
if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >= 60:
return "D"
else:
return "F"
avg = get_average(lloyd)
t = get_letter_grade(avg)
print t
def get_class_average(students):
results = []
students = [lloyd, alice, tyler]
a= get_average(students)
r= results.append(a)
return r
student = [lloyd, alice, tyler]
for key in student:
a = get_class_average(key)
print a
您的get_class_average()
函數希望傳遞給整個學生列表,而不是每個學生。
刪除for key in student:
的for key in student:
循環:
students = [lloyd, alice, tyler]
a = get_class_average(students)
在get_class_average()
函數中,您似乎返回得太早了 ; 使return
不縮進不成為循環的一部分。 results.append()
返回None
,因為它改變了results
就地 :
def get_class_average(students):
results = []
for key in students:
a= get_average(key)
results.append(a)
return results
但是,這仍然不能計算出整個班級的平均水平。 它只是將每個學生的平均值收集到一個列表中。
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