使用FileDialog打開工作簿並在Excel VBA中進行操作

Question

我正在學習如何使用Excel宏，並找到了以下代碼：

Dim fd As Office.FileDialog

Set fd = Application.FileDialog(msoFileDialogFilePicker)

With fd

    .AllowMultiSelect = False
    .Title = "Please select the file to kill his non colored cells"
    .Filters.Add "Excel", "*.xls"
    .Filters.Add "All", "*.*"

    If .Show = True Then
        txtFileName = .SelectedItems(1)
    End If

End With

此代碼將打開FileDialog。 如何打開所選的Excel文件而不覆蓋以前打開的Excel文件？

Answer 1

謝謝Frank.i有了這個主意。 這是工作代碼。

Option Explicit
Private Sub CommandButton1_Click()

  Dim directory As String, fileName As String, sheet As Worksheet, total As Integer
  Dim fd As Office.FileDialog

  Set fd = Application.FileDialog(msoFileDialogFilePicker)

  With fd
    .AllowMultiSelect = False
    .Title = "Please select the file."
    .Filters.Clear
    .Filters.Add "Excel 2003", "*.xls?"

    If .Show = True Then
      fileName = Dir(.SelectedItems(1))

    End If
  End With

  Application.ScreenUpdating = False
  Application.DisplayAlerts = False

  Workbooks.Open (fileName)

  For Each sheet In Workbooks(fileName).Worksheets
    total = Workbooks("import-sheets.xlsm").Worksheets.Count
    Workbooks(fileName).Worksheets(sheet.Name).Copy _
        after:=Workbooks("import-sheets.xlsm").Worksheets(total)
  Next sheet

  Workbooks(fileName).Close

  Application.ScreenUpdating = True
  Application.DisplayAlerts = True

End Sub

Answer 2

除非我誤解了您的問題，否則您只能打開一個只讀文件。 這是一個簡單的示例，沒有進行任何檢查。

要從用戶獲取文件路徑，請使用此功能：

Private Function get_user_specified_filepath() As String
    'or use the other code example here.
    Dim fd As Office.FileDialog
    Set fd = Application.FileDialog(msoFileDialogFilePicker)
    fd.AllowMultiSelect = False
    fd.Title = "Please select the file."
    get_user_specified_filepath = fd.SelectedItems(1)
End Function

然后，只需以只讀方式打開文件並將其分配給變量即可：

dim wb as workbook
set wb = Workbooks.Open(get_user_specified_filepath(), ReadOnly:=True)