如何使用函數將嵌套的JSON映射到Object結構？

Question

我想映射這樣的結構：

{ 
    "stuff": {
        "onetype": [
            {"id":1,"name":"John Doe"},
            {"id":2,"name":"Don Joeh"}
        ],
        "othertype": {"id":2,"company":"ACME"}
    }, 
    "otherstuff": {
        "thing": "some value"
     }
}

到包含2個對象數組（對象和其他內容）的對象。 我想為此JSON對象構建一個原型，以便我可以使用所有功能。 我希望能夠做這樣的事情（樹是父對象）。 tree.display() ，其中的顯示函數將以一種類型的數組進入數組，並在包含的對象上調用函數display。

有一個簡單的方法嗎？ 有人可以給我指出如何做到這一點的例子嗎？ 我可以使用$.extend類的功能嗎？

這不起作用：

$(document).ready(function(){
    JSONString = '\
        {"stuff": \
            {"onetype": \
                [{"id":1,"name":"John Doe"},\
                {"id":2,"name":"Don Joeh"}],\
            "othertype": \
                {"id":2,"company":"ACME"}\
            }, \
        "otherstuff": {"thing": "some value" }\
        }';

    function Tree () {
        this.stuff = new StuffObject();
        this.otherstuff;
        this.showValue = function () {
            $("body").append(this.otherstuff.thing);
        }
    }

    function StuffObject () {
        this.onetype = new Array();
        this.othertype = new OthertypeObject();
    }

    function OthertypeObject () {
        this.id = 0;
        this.company = "unspecified";
        this.showCompany = function(){
            console.log(this.company);
        }
    }

    var firstTree = $.extend(true, new Tree, JSON.parse(JSONString));
    console.log(firstTree);
    firstTree.showValue();
    firstTree.stuff.othertype.showCompany();
});

Answer 1

如果您只想顯示某些特定字段，則可以嘗試此操作，它將給出公司名稱：

<script>
    alert("see this");
    JSONString = '\
        {"stuff": \
            {"onetype": \
                [{"id":1,"name":"John Doe"},\
                {"id":2,"name":"Don Joeh"}],\
            "othertype": \
                {"id":2,"company":"ACME"}\
            }, \
        "otherstuff": {"thing": "some value" }\
        }';

    function Tree () {
        this.stuff = new StuffObject();
        this.otherstuff;
        this.showValue = function () {
            $("body").append(this.otherstuff.thing);
        }
    }

    function StuffObject () {
        this.onetype = new Array();
        this.othertype = new OthertypeObject();
    }

    function OthertypeObject () {
        this.id = 0;
        this.company = "unspecified";
        this.showCompany = function(){
            console.log(this.company);
        }
    }

    var firstTree = $.extend(true, new Tree, JSON.parse(JSONString));
   // var x=json_encode(firstTree);
    console.log(firstTree);
    var x = JSON.stringify(firstTree.stuff.othertype.company);
    alert(x);

</script>