[英]Can't retrieve variable from php
PHP文件:
<?php
#Communication with the API
require_once 'api.php';
$cloudkey = new CloudKey($user_id, $api_key);
if(isset($_FILES["FileInput"]) && $_FILES["FileInput"]["error"]== UPLOAD_ERR_OK)
{
//Deleted Code: putting the uploaded files in my server.
if(move_uploaded_file($_FILES['FileInput']['tmp_name'], $UploadDirectory.$NewFileName ))
{
$video_file = "/home/george/public_html/q/";
$video_file = $video_file . $NewFileName;
#Sending the video from my server to the cloud server
$res = $cloudkey->file->upload_file($video_file);
#The cloud server will create a link
$source_url = $res->url;
#The cloud server will convert the video very fastly
while(1) {
#Deleted Code: Conversion
if ($asset->status == 'ready') {
# A lot of code. It will convert the videos here and if it succeeds it will stop.
break;
# If the conversion fails, display error
} else if ($asset->status == 'error') {
echo "Error while transcoding the media\n";
}
sleep(1);
}
# Getting the URL of a thumbnail
echo $thumb = $cloudkey->media->get_stream_url(array('id' => $media_id, 'asset_name' => 'jpeg_thumbnail_source'));
}else{
die('error uploading File!');
}
}
else
{
die('Something went wrong!');
}
?>
HTML檔案:
{literal}
<script type="text/javascript">
$(document).ready(function() {
var options = {
target: '#output', // target element(s) to be updated with server response
beforeSubmit: beforeSubmit, // pre-submit callback
success: afterSuccess, // post-submit callback
uploadProgress: OnProgress, //upload progress callback
resetForm: true // reset the form after successful submit
};
//function after succesful file upload (when server response)
function afterSuccess()
{
$('#loading-img').hide(); //hide submit button
$('#progressbox').fadeOut(); //hide progress bar
//I WANT TO INSERT SOMETHING HERE.
}
//progress bar function
function OnProgress(event, position, total, percentComplete)
{
//DOES NOT INTEREST YOU
});
</script>
{/literal}
<div id="output"></div>
我正在使用smarty模板引擎。 我有一個html上載表格,該表格將與php文件progressupload.php進行通信,其中php文件將轉換視頻(使用API服務)並在完成時返回響應。
當用戶上傳視頻文件時,ajax將接管顯示的百分比(以html格式),並將文件發送到progressupload.php ,當progressupload.php完成轉換后,只需將回顯的所有內容輸出到php中這在html文件中(我不知道為什么): <div id="output"></div>
。
我想要的是:
當progressupload.php完成轉換后,它將生成一個縮略圖(屏幕快照)並將其鏈接存儲在$thumb
。 我想檢索$thumb
並將其顯示給用戶使用jquery。
現在,如果您查看HTML代碼,則afterSuccess()
是我要向用戶顯示縮略圖的函數:
function afterSuccess()
{
$('#loading-img').hide(); //hide submit button
$('#progressbox').fadeOut(); //hide progress bar
//I WANT TO SHOW THE THUMBNAIL HERE.
}
我刪除了很多不必要的代碼,這些代碼可能會使您分心。 請記住,我使用的是smarty模板引擎,我的html文件未以.php結尾 ,我無法直接回顯該變量。 創建變量后,如何檢索php變量並將其放入jquery方法中。
我懷疑如果直接在頁面加載時檢索變量,由於鏈接需要創建時間(上載,轉換),因此它不會成功獲取$thumb
。 如何檢索該$thumb
?
假設您正在使用jQuery.ajax();
$ .ajax“成功”回調中的第一個參數是從服務器端返回的參數。
function afterSuccess( response /** this is what returned from your server **/ )
{
$('#loading-img').hide(); //hide submit button
$('#progressbox').fadeOut(); //hide progress bar
//I WANT TO INSERT SOMETHING HERE.
console.log(response); // here you can access your $thumbnail
// below code is untested but it should work
// $("#output").html("<img src='"+response+"' class='thumbnail' />");
}
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