[英]How to retrieve result of COUNT(*) statement through PHP
如何使用PHP檢索以下COUNT(*)MYSQL語句的結果?
MYSQL
$sql= mysql_query ("
select count(*)
from orders o
WHERE order_status IN
('Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order')
GROUP BY FIELD
(order_status,'Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order')
");
以上查詢結果
count(*)
226
19130
593
2603
2892
我嘗試了以下代碼按順序檢索每一行-
PHP
$row = mysql_fetch_row($sql);
echo $row[0];
echo $row[1];
echo $row[2];
echo $row[3];
echo $row[4];
產生以下錯誤: Notice: Undefined offset: 1 ...
我知道我缺少了一些非常簡單的東西,但是請有人告訴我調用COUNT(*)查詢結果的正確方法。
您的查詢返回5行。 您必須遍歷它們並顯示列:
while($row = mysql_fetch_row($sql)){
echo $row[0];
}
另請參閱文檔
使用別名進行計數也很有意義。
$sql= mysql_query = "
select count(*) as countValue
from orders o
WHERE order_status IN
('Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order')
GROUP BY FIELD
(order_status,'Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order')
";
while($row = mysql_fetch_row($sql)){
echo $row["countValue"];
}
警告:從PHP 5.5.0開始不推薦使用mysql_擴展名,以后會刪除它。 相反,應使用MySQLi或PDO_MySQL擴展。
您需要添加循環以獲取所有數據並使用mysqli而不是mysql。
像這樣的東西
$sql= "select count(*) as total from orders o WHERE order_status IN
('Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order') GROUP BY FIELD (order_status,'Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order')"
$result = mysqli_query($con, $sql);
while($row = mysqli_fetch_array($result)) {
echo $row['total'];
echo "<br>";
}
您也可以對mysql而不是mysqli使用相同的方法,但是mysqli對於將來的使用會更好。
$result = mysql_query($sql);
while($row = mysql_fetch_row($sql)){
echo $row['total'];
echo "<br>";
}
$sql= mysql_query ("
select count(*) as nbre
from orders o
WHERE order_status IN
('Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order')
GROUP BY FIELD
(order_status,'Printed Order', 'Charged Order', 'Exchanged Order', 'Refunded Order', 'Cancelled Order')
");
echo $row[0]['nbre'];
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.