[英]Flask UnboundField QuerySelectField
我在Flask中使用QuerySelectFileds遇到問題:
class User(db.Model):
id = db.Column(db.Integer, primary_key = True)
username = db.Column(db.String(64), unique = True)
clearname = db.Column(db.String(254))
password = db.Column(db.String(254))
role = db.Column(db.Integer)
def __init__(self, username, clearname, password, role):
self.username = username
self.clearname = clearname
self.password = password
self.role = role
def __repr__(self):
return 'Benutzer %r' % self.username
def get_User():
return db.session.query(User.username).all()
class f1(Form):
us = QuerySelectField(u'hello', query_factory = get_User())
我的確看到了我的用戶(“ Admin”和“ test1”),但未在選擇字段中看到。 我得到的是:
<UnboundField(QuerySelectField, (u'hello',), {'query_factory': [(u'Admin',), (u'test1',)]})>
如何正確創建QuerySelectField?
有人可以幫忙嗎?
謝謝!
編輯2014-08-18:該視圖包含:
return render_template('login.html',
title = 'Sign In',
form = form)
編輯2014-08-18:
首先:感謝您的答復!
同時,我獲得了一些成功-這是代碼(基於Flask Mega-Tutorial):
run.py:
#!env/bin/python
from app import app
app.run(debug = True)
app / init .py:
from flask import Flask
from flask.ext.sqlalchemy import SQLAlchemy
app = Flask(__name__)
app.config.from_object('config')
db = SQLAlchemy(app)
from app import views, models
app / models.py:
from app import db
ROLE_USER = 100
ROLE_ADMIN = 0
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key = True)
username = db.Column(db.String(64), index = True, unique = True)
clearname = db.Column(db.String(64))
password = db.Column(db.String(256))
role = db.Column(db.SmallInteger, default = ROLE_USER)
def __repr__(self):
return '<User %r>' % (self.username)
def get_User():
return User.query
app / forms.py:
from flask.ext.wtf import Form
from wtforms import TextField, BooleanField
from wtforms.validators import Required
from wtforms.ext.sqlalchemy.fields import QuerySelectField
from .models import get_User
class LoginForm(Form):
openid = TextField('openid', validators = [Required()])
remember_me = BooleanField('remember_me', default = False)
user = QuerySelectField(u'User', query_factory=get_User)
app / views.py:
from flask import render_template, flash, redirect
from app import app
from .forms import LoginForm
@app.route('/')
@app.route('/index')
def index():
return "Hello, World!"
@app.route('/login')
def login():
form = LoginForm()
return render_template('login.html', title='Eingloggen!', form=form)
app / templates / login.html:
<!-- extend from base layout -->
{% extends "base.html" %}
{% block content %}
<h1>Sign In</h1>
<form action="" method="post" name="login">
{{form.hidden_tag()}}
<p>
Please enter your OpenID:<br>
{{form.openid(size=80)}}<br>
</p>
<p>{{form.remember_me}} Remember Me</p>
<p>{{form.user}} The QuerySelectField :-)</p>
<p><input type="submit" value="Sign In"></p>
</form>
{% endblock %}
現在QuerySelectField出現與__repr__
我的類用戶的:
----------------
| <User 'test1'> |
| <User 'Admin'> |
----------------
select id="user" name="user"><option value="1"><User 'test1'></option><option value="2"><User 'Admin'></option></select>
但是,我該怎么辦查詢像select * from username
,並有在selectField用戶名TEST1和管理員在不改變__repr__
?
例如,也許可以select * from role
另一個查詢select * from role
而我想擁有諸如get_User(),get_Roles()之class User
函數。將此類函數放入class User
本身是個好主意嗎?
只需將()保留在get_user的最后一行
def get_User():
return db.session.query(User.username).all # <----
在您的案例書中,query_factory回調應返回完整的實體,而不是書的ID。 我相信QuerySelectField必須嘗試使用查詢結果,就好像它們是映射對象一樣,而id(返回為KeyedTuple實例)不是。
我認為這是編寫回調函數的正確方法:
def get_User():
return User.query
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