[英]Insert data to mysql table ends up with blank rows?
我正在顯示mysql數據庫中的所有問題。 當我單擊提交名稱時,正確保存了電子郵件地址。
但是question_id和answer_id只是保存空白行? 為什么?
我想用sql函數插入一些答案嗎?
index.php:
include ('connection.php');
function getQuestions($con) {
// generate all quetions
$query = "SELECT * FROM questions";
$result = @mysqli_query($con, $query);
if ($result) {
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
$body = $row['question_body'];
$question_id = $row['question_id'];
echo '
<tr>
<form action="insert.php" method="POST">
<td>'.$question_id, $body.'</td>
<td><input type="radio" name="answer_value" value="1"></td>
<td><input type="radio" name="answer_value" value="2"></td>
<td><input type="radio" name="answer_value" value="3"></td>
</tr>
</form>
<br/>';
}
}
}
echo'
<form action="insert.php" method="post">
Firstname: <input type="text" name="firstname">
Lastname: <input type="text" name="lastname">
Email: <input type="text" name="email">
<input type="submit">
</form>';
insert.php:
<?php
include ('connection.php');
// escape variables for security
$firstname = mysqli_real_escape_string($con, $_POST['firstname']);
$lastname = mysqli_real_escape_string($con, $_POST['lastname']);
$email = mysqli_real_escape_string($con, $_POST['email']);
$sql="INSERT INTO users (FirstName, LastName, Email)
VALUES ('$firstname', '$lastname', '$email')";
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
echo "User added <br>";
// escape variables for security
$question_id = mysqli_real_escape_string($con, $_POST['question_id']);
$answer_value = mysqli_real_escape_string($con, $_POST['answer_value']);
$sql="INSERT INTO answers (question_id, answer_value)
VALUES ('$question_id', '$answer_value')";
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
echo "Answers added";
mysqli_close($con);
?>
您有兩個單獨的表格。 answer_value
業務在您在db fetch循環中創建的業務中定義。 但是您的“提交”按鈕實際上是另一種形式,即您擁有姓名/電子郵件形式的地方。
里面只有一個表單標簽定義的字段會得到提交。 在某些完全不同的<form>...</form>
塊中定義的字段將被完全忽略/不相關,也將不會提交。
換句話說,您需要
<form ...>
[radio button set for question #1]
[radio button set for question #2]
...
[input fields for name/email]
</form>
不
<form ... >
[radio button set #1]
</form>
<form ...>
[radio button set #2]
</form>
<form ...>
[name/email input fields]
</form>
您沒有在HTML表單中准備question_id。 它會像這樣:
echo '<tr>
<form atcion="insert.php" method="post">
<td><input type="hidden" name="question_id" value="'.$question_id.'">'.$question_id, $body.'</td>
<td><input type="radio" name="answer_value" value="1"></td>
<td><input type="radio" name="answer_value" value="2"></td>
<td><input type="radio" name="answer_value" value="3"></td>
</tr>
</form>';
您沒有在問題表單中提交值。 要在一個POST中提交所有條目,您需要所有元素都在同一表單上。
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