[英]Calling from a database using a switch statement: PHP
布局是塊/模塊化的,所以我需要將一個類應用於每個div。 問題是,當我在瀏覽器中預覽時,代碼循環再次從第一種情況開始-跳過了數據庫中的一項,並在情況1下顯示了下一項。
$result = mysqli_query($connection, "SELECT * FROM products");
$index = 1;
while($row = mysqli_fetch_array($result)) {
$float = "";
switch ($index) {
case 1: $float = "large-left";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 2: $float = "mini-left";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 3: $float = "mini-right";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 4: $float = "mini-left";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 5: $float = "mini-right";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 6: $float = "large-right";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 7: $float = "mini-left";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 8: $float = "mini-right";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 9: $float = "mini-left";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
case 10: $float = "mini-right";
echo "<div class=\"$float\"><img src=\"" . $row['product_imagepath'] . "\"/></div>";
break;
default: $index = 0;
break;
};
$index++;
};
mysqli_close($result);
?>
任何建議/替代方法將不勝感激!
您給$ index作為1
$index = 1;
因此,每次都會轉到案例1。 它不是動態的。
如果我理解正確,則希望將10種產品“分組”
$result = mysqli_query($connection, "SELECT * FROM products");
$index = 1;
while($row = mysqli_fetch_array($result)) {
if ($index % 10 == 1) {
$float = 'large-left';
}
else {
if($index % 2 == 1) {
$float = 'mini-right';
}
else {
$float = 'mini-left';
}
}
echo '<div class="' . $float . '"><img src="' . $row['product_imagepath'] . '"></div>';
$index++;
}
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