通過jquery AJAX將javascript數組傳遞給php

Question

我在將我的JavaScript數組傳遞到php文件時遇到問題。 我知道JS數組具有正確的用戶輸入數據，因為我已經通過使用toString（）並將其打印在我的網頁上進行了測試。 我的計划是使用AJAX將JS數組發送到我的php腳本，但是我對使用AJAX還是陌生的，所以很有可能我做錯了什么。 我瀏覽了很多有同樣問題的人，但是我嘗試過的所有方法到目前為止都還沒有奏效。 我現在只知道JS數組中的數據很好，但是當我嘗試通過AJAX將其傳遞給php文件時，php腳本不會接收到它。 我知道這一點，因為我不斷收到未定義的變量錯誤。 老實說，我不確定是否要嘗試將數組傳遞給php腳本，還是要如何將數組值分配給php端變量的問題。 目前，我的代碼如下：

我的Javascript：

function createAsset(str, str, str, str, str, str, str, str, str)
    {
        var aID = assetID.value;
        var aName = assetName.value;
        var pPrice = purchasedPrice.value;
        var pDate = purchasedDate.value;
        var supp = supplier.value;
        var cValue = currentValue.value;
        var aOwner = actualOwner.value;
        var wEdate = warrantyExpiryDate.value;
        var dDate = destroyedDate.value;

        //document.write(aID);
        //var dataObject = new Array()
        //dataObject[0] = aID;
        //dataObject[1] = aName;
        //dataObject[2] = pPrice;
        //dataObject[3] = pDate;
        //dataObject[4] = supp;
        //dataObject[5] = cValue; 
        //dataObject[6] = aOwner;
        //dataObject[7] = wEdate;
        //dataObject[8] = dDate;
        //dataObject.toString();
        //document.getElementById("demo").innerHTML = dataObject;

        var dataObject = { assitID: aID,
                           assitName: aName,
                           purchasedPrice: pPrice,
                           purchasedDate: pDate,
                           supplier: supp,
                           currentValue:  cValue, 
                           actualOwner: aOwner,
                           warrantyExpiryDate: wEdate,
                           destroyedDate: dDate };  

         $.ajax
         ({
            type: "POST",
            url: "create_asset_v1.0.php",
            data: dataObject, 
            cache: false,
            success: function()
            {
                alert("OK");
                location.reload(true);
                //window.location = 'create_asset_v1.0.php';
            }
        }); 
    }

我的PHP：

<?php
// Get Create form values and assign them to local variables.
$assetID = $_POST['aID'];
$assetName = $_POST['aName'];
$purchasedPrice = $_POST['pPrice'];
$purchasedDate = $_POST['pDate'];
$supplier = $_POST['supp'];
$currentValue = $_POST['cValue'];
$actualOwner = $_POST['aOwner'];
$warrantyExpiryDate = $_POST['wEdate'];
$destroyedDate = $_POST['dDate'];

// Connect to the SQL server.
$server='PC028\ZIRCONASSETS';               //serverName\instanceName
$connectinfo=array("Database"=>"zirconAssetsDB");
$conn=sqlsrv_connect($server,$connectinfo);

if($conn)
{
    echo "Connection established.<br/><br/>";
}
else
{
    echo "Connection couldn't be established.<br/><br/>";
    die(print_r( sqlsrv_errors(), true));
} 

// Query the database to INSERT record.
$sql = "INSERT INTO dbo.inHouseAssets 
        (Asset_ID, Asset_Name, Perchased_Price, Date_Perchased, Supplier, Current_Value, Actual_Owner,Worranty_Expiry_Date, Destroyed_Date) 
        VALUES 
        (?, ?, ?, ?, ?, ?, ?, ?, ?)";

$params = array($assetID, $assetName, $purchasedPrice, $purchasedDate, $supplier, $currentValue, $actualOwner, $warrantyExpiryDate, $destroyedDate);

// Do not send query database if one or more field have no value.
if($assetID && $assetName && $purchasedPrice && $purchasedDate && $supplier && $currentValue && $actualOwner && $warrantyExpiryDate && $destroyedDate != '')
{
    $result = sqlsrv_query( $conn, $sql, $params);

    // Check if query was executed with no errors.
    if( $result === false ) 
    {
        // If errors occurred print out SQL console data.  
        if( ($errors = sqlsrv_errors() ) != null) 
        {
            foreach( $errors as $error ) 
            {
                echo "SQLSTATE: ".$error[ 'SQLSTATE']."<br/>";
                echo "code: ".$error[ 'code']."<br/>";
                echo "message: ".$error[ 'message']."<br/>";
            }
        }
    }
    else
    {
        echo "Record Created!<br/>";
    }
}

// Close server connection
sqlsrv_close( $conn );
if($conn)
{
    echo "<br/>Connection still established.";
}
else
{
    echo "<br/>Connection closed.";
}?>

就像額外的信息（如果它在我的代碼中不明顯）一樣，我試圖將用戶數據從html表單發送到php腳本，該腳本對其進行處理並使用它來查詢MSSQL數據庫。 我現在正在使用的此功能是創建數據庫條目功能。

Answer 1

您需要匹配通過AJAX發送的密鑰：

var dataObject = { assitID: aID,
                           assitName: aName,
                           purchasedPrice: pPrice,
                           purchasedDate: pDate,
                           supplier: supp,
                           currentValue:  cValue, 
                           actualOwner: aOwner,
                           warrantyExpiryDate: wEdate,
                           destroyedDate: dDate };

使用POST數組鍵：

$assetID = $_POST['aID'];
$assetName = $_POST['aName'];
$purchasedPrice = $_POST['pPrice'];
$purchasedDate = $_POST['pDate'];
$supplier = $_POST['supp'];
$currentValue = $_POST['cValue'];
$actualOwner = $_POST['aOwner'];
$warrantyExpiryDate = $_POST['wEdate'];
$destroyedDate = $_POST['dDate'];

您的代碼應如下所示：

$assetID = $_POST['assitID'];
$assetName = $_POST['assitName'];
$purchasedPrice = $_POST['purchasedPrice'];
...

Answer 2

您正在讀取錯誤的鍵。

$assetID = $_POST['aID'];

一定是：

$assetID = $_POST['assitID'];

根據您發送的對象。