[英]Conditionally add a field to the output of the query
僅在user_answer.user_id = 10時才希望選擇user_answer.status
我使用此SQL查詢從多個表( 問題 , q_t , 標簽 , user_answer )返回結果
SQL:
select question.text,group_concat(tag.text), count(user_answer.question_id) as tt
from question
left join q_t on question.id = q_t.wall_id
left join user_answer on question.id = user_answer.question_id
left join tag on q_t.tag_id = tag.id
where question.id in (1000001,1000002,1000003,1000004,1000005)
group by question.text
order by field(question.id,1000001,1000002,1000003,1000004,1000005)
結果:
text text tt
where is England? Geography,Continent 33
how many ...? sport,Europe 2
我需要從user_answer表中添加新的select user_answer.status ,並附帶條件(僅適用於檢索此選擇):
select user_answer.status
where user_answer.user_id = 10
如何添加此條件?
謝謝,
您可以使用CASE WHEN來做到這一點:
select
question.text,group_concat(tag.text),
count(user_answer.question_id) as tt,
CASE WHEN user_answer.user_id = 10 THEN user_answer.status ELSE NULL END as status
from question
left join q_t on question.id = q_t.wall_id
left join user_answer on question.id = user_answer.question_id
left join tag on q_t.tag_id = tag.id
where question.id in (1000001,1000002,1000003,1000004,1000005)
group by
question.text,
CASE WHEN user_answer.user_id = 10 THEN user_answer.status ELSE NULL END
order by field(question.id,1000001,1000002,1000003,1000004,1000005);
如果您希望將狀態應用於所有問題,則可以使用MAX:
select
question.text,group_concat(tag.text),
count(user_answer.question_id) as tt,
MAX(CASE
WHEN user_answer.user_id = 10
THEN user_answer.status
ELSE NULL
END) as status
from question
left join q_t on question.id = q_t.wall_id
left join user_answer on question.id = user_answer.question_id
left join tag on q_t.tag_id = tag.id
where question.id in (1000001,1000002,1000003,1000004,1000005)
group by
question.text
order by field(question.id,1000001,1000002,1000003,1000004,1000005);
select question.text,group_concat(tag.text), count(user_answer.question_id) as tt
,if((user_answer.id=10),(select user_answer.status),(''))as status
from question`enter code here`
left join q_t on question.id = q_t.wall_id
left join user_answer on question.id = user_answer.question_id
left join tag on q_t.tag_id = tag.id
where question.id in (1000001,1000002,1000003,1000004,1000005)
group by question.text
order by field(question.id,1000001,1000002,1000003,1000004,1000005)
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