[英]Group data weekly according to passed date range in mysql cake php
我有一個包含以下數據的表作業
+----+------------+--------+---------------------+
| id | project_id | status | modified |
+----+------------+--------+---------------------+
| 1 | 1 | 0 | 2014-08-23 19:48:48 |
| 2 | 1 | 0 | 2014-08-29 18:18:39 |
| 3 | 1 | 0 | 2014-08-23 19:58:55 |
| 44 | 1 | 0 | 2014-08-23 19:45:50 |
| 45 | 1 | 2 | 2014-08-03 14:38:35 |
| 46 | 1 | 3 | 2014-08-05 14:38:35 |
| 47 | 1 | 2 | 2014-08-07 14:38:35 |
| 48 | 1 | 3 | 2014-08-10 14:38:35 |
| 49 | 2 | 4 | 2014-08-14 14:38:35 |
| 50 | 1 | 0 | 2014-08-23 19:43:01 |
| 51 | 1 | 2 | 2014-08-15 14:38:35 |
| 52 | 1 | 3 | 2014-08-18 14:38:35 |
| 53 | 1 | 0 | 2014-08-23 19:49:05 |
| 54 | 1 | 4 | 2014-08-22 14:38:35 |
| 55 | 1 | 2 | 2014-09-03 14:38:59 |
| 56 | 1 | 0 | 2014-08-23 19:59:23 |
| 57 | 1 | 3 | 2014-08-27 14:38:35 |
| 58 | 1 | 4 | 2014-09-03 14:39:04 |
| 59 | 1 | 0 | 2014-08-27 17:28:45 |
| 60 | 1 | 1 | 2014-08-27 17:29:00 |
| 61 | 1 | 1 | 2014-08-27 17:29:17 |
| 62 | 1 | 0 | 2014-08-29 16:36:07 |
| 63 | 1 | 0 | 2014-08-29 16:37:24 |
| 64 | 1 | 0 | 2014-08-29 18:19:01 |
| 65 | 1 | 0 | 2014-08-29 19:17:20 |
| 66 | 1 | 1 | 2014-08-29 19:17:36 |
| 67 | 1 | 1 | 2014-08-29 19:17:54 |
| 68 | 1 | 0 | 2014-08-29 19:26:16 |
| 69 | 1 | 1 | 2014-08-29 19:26:34 |
| 70 | 1 | 1 | 2014-08-29 19:26:54 |
| 71 | 1 | 0 | 2014-08-30 19:33:59 |
| 72 | 1 | 1 | 2014-08-30 19:34:23 |
| 73 | 1 | 1 | 2014-08-30 19:35:42 |
| 74 | 1 | 1 | 2014-08-30 19:36:39 |
| 75 | 1 | 0 | 2014-08-30 19:40:52 |
| 76 | 1 | 0 | 2014-08-30 20:42:02 |
| 77 | 1 | 0 | 2014-08-30 21:27:38 |
| 78 | 1 | 1 | 2014-08-30 21:28:28 |
| 79 | 1 | 1 | 2014-08-30 21:28:59 |
| 80 | 1 | 0 | 2014-08-30 21:47:02 |
| 81 | 1 | 1 | 2014-08-30 21:47:40 |
| 82 | 1 | 1 | 2014-08-30 21:48:20 |
| 83 | 2 | 3 | 2014-08-23 18:23:12 |
| 84 | 2 | 4 | 2014-08-23 18:23:12 |
| 85 | 1 | 4 | 2014-08-23 18:23:12 |
+----+------------+--------+---------------------+
我希望根據我從前端經過的“開始”和“結束”日期,每周從中獲取數據。 因此,讓我們假設想要從'2014-07-15'到'2014-09-15'的數據應該每周匯總,並給出每個項目在特定一周內狀態為(2,3,4)的所有工作的總和。
我的結果應該是這樣的
+--------------+---------------+---------------------+
| project_name | reviewed_jobs | modified |
+--------------+---------------+---------------------+
| Project 1 | 0 | 2014-07-15 14:38:35 |
| Project 1 | 0 | 2014-07-22 14:38:35 |
| Project 1 | 1 | 2014-07-29 14:38:35 |
| Project 1 | 3 | 2014-08-05 14:38:35 |
| Project 1 | 2 | 2014-08-12 14:38:35 |
| Project 1 | 2 | 2014-08-19 18:23:12 |
| Project 1 | 1 | 2014-08-26 19:48:48 |
| Project 1 | 2 | 2014-09-02 18:18:39 |
| Project 1 | 0 | 2014-09-09 14:38:59 |
| Project 2 | 0 | 2014-07-15 14:38:35 |
| Project 2 | 0 | 2014-07-22 14:38:35 |
| Project 2 | 0 | 2014-07-29 14:38:35 |
| Project 2 | 0 | 2014-08-05 14:38:35 |
| Project 2 | 1 | 2014-08-12 14:38:35 |
| Project 2 | 2 | 2014-08-19 18:23:12 |
| Project 2 | 0 | 2014-08-26 19:48:48 |
| Project 2 | 0 | 2014-09-02 18:18:39 |
| Project 2 | 0 | 2014-09-09 14:38:59 |
+--------------+---------------+---------------------+
到目前為止,我嘗試使用原始查詢和Cake php方法進行的操作:
原始查詢:
SELECT projects.name as project_name,
SUM(if((jobs.status=2 || jobs.status=3 || jobs.status=4), 1, 0)) as reviewed_jobs,
jobs.modified FROM jobs LEFT JOIN projects ON jobs.project_id=projects.id
WHERE jobs.modified >= '2014:08:03 00:00:00' AND jobs.modified <= '2014:09:03 23:59:59'
GROUP BY projects.name, WEEK(jobs.modified)
ORDER BY DATE(jobs.modified) ASC;
但它給出以下結果
+--------------+---------------+---------------------+
| project_name | reviewed_jobs | modified |
+--------------+---------------+---------------------+
| Project 1 | 3 | 2014-08-03 14:38:35 |
| Project 1 | 2 | 2014-08-10 14:38:35 |
| Project 2 | 1 | 2014-08-14 14:38:35 |
| Project 2 | 2 | 2014-08-23 18:23:12 |
| Project 1 | 3 | 2014-08-23 19:48:48 |
| Project 1 | 1 | 2014-08-29 18:18:39 |
| Project 1 | 2 | 2014-09-03 14:38:59 |
+--------------+---------------+---------------------+
這顯然是不希望的,並且與我想要的有所不同,並且存在一些潛在的問題,例如
如果沒有得到特定日期的數據(在這種情況下,即2014-08-17),它將跳過該周或從下一個可用日期開始計數。
結果不是根據查詢中傳遞的日期,而是根據表中的數據(表中可用的日期)。
CakePHP方式:
$options['joins']=array(array('table' => 'projects',
'alias' => 'Project',
'type' => 'LEFT',
'conditions' => array(
'Project.id = Job.project_id',
)
));
$options['fields'] = array(
'Project.name',
'SUM(if((Job.status=2 || Job.status=3 || Job.status=4), 1, 0)) as reviewed',
'DATE(Job.modified) as modified'
);
$options['order'] = array('modified'=>'ASC');
$options['conditions']=array(
array("Job.modified >=" => $from_date->format("Y-m-d") . ' 00:00:00'),
array("Job.modified <=" => $to_date->format("Y-m-d") . ' 23:59:59')
);
$options['group'] = array('Project.name', 'WEEK(Job.modified)');
任何幫助都將是可觀的
謝謝
在mysql中,您將需要另一個包含所有星期幾的表,以便您也可以加入該表,並因此返回Jobs表中沒有任何條目的星期幾。
快速而骯臟的構建周數據的方法:
SELECT STR_TO_DATE(CONCAT(yr.yy,'-',wk1.d,wk2.d,'-01'), '%Y-%u-%w') yyyywkd FROM
(SELECT 0 d UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5) wk1,
(SELECT 0 d UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) wk2,
(SELECT '2013' yy UNION SELECT '2014') yr
WHERE CONCAT(wk1.d,wk2.d) > 0 AND CONCAT(wk1.d,wk2.d) < 54
在子作業中加入作業表的子查詢中嘗試此操作。
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