[英]Select row with the highest date in MySQL
我有一個表,每個用戶每天都有行。
我想按月和年分組以生成給定月份的摘要。
問題是,它正在選擇第一行的值(即9月1日而不是9月5日),這給了我錯誤的數字,因為我想要該列的最新運行總計。
我努力了:
SELECT SUM(prospectCount) FROM report_sales_day AS RSD
WHERE userId = 93
AND YEAR(date) = YEAR('2014-09-01')
AND MONTH(date) = MONTH('2014-09-01')
AND (SELECT MAX(RSDI.date)
FROM report_sales_day AS RSDI
WHERE MONTH(RSDI.date) = MONTH(RSD.date)
AND YEAR(RSDI.date) = YEAR(RSD.date)) = MAX(date)
GROUP BY YEAR(date), MONTH(date)
但這只是給我一個錯誤,我想不出其他任何方法來做到這一點。
有誰知道我需要做些什么才能達到我想要的結果?
我的表中有很多列,有些需要SUM(),AVG(),而另一些只需要給定月份的最后一個值。
嘗試這個:
SELECT SUM(prospectCount)
FROM report_sales_day AS RSD
INNER JOIN (SELECT userId, MAX(RSDI.date) AS `date`
FROM report_sales_day AS RSDI
WHERE MONTH(RSDI.date) = MONTH('2014-09-01') AND YEAR(RSDI.date) = YEAR('2014-09-01')
) AS A ON RSD.userId = A.userId AND RSD.date = A.date
WHERE userId = 93 AND YEAR(RSD.date) = YEAR('2014-09-01') AND
MONTH(RSD.date) = MONTH('2014-09-01')
GROUP BY YEAR(RSD.date), MONTH(RSD.date)
我認為您的查詢應該是這樣的。 您必須在`date`附近使用反引號
SELECT SUM(prospectCount) FROM report_sales_day AS RSD
WHERE userId = 93
AND YEAR(`date`) = YEAR('2014-09-01')
AND MONTH(`date`) = MONTH('2014-09-01')
AND MAX(`date`) = (SELECT MAX(RSDI.date)
FROM report_sales_day
WHERE MONTH(RSDI.date) = MONTH(RSD.date)
AND YEAR(RSDI.date) = YEAR(RSD.date))
GROUP BY YEAR(`date`), MONTH(`date`)
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