[英]Couldn't find Listing with 'id'=all, Search Form
所以這很奇怪。 我跟着這個railscast http://railscasts.com/episodes/37-simple-search-form ,在我實現了它之后看起來像這樣
index.html.erb
<%= form_tag findjobs_path, :method => 'get' do %>
<p>
<%= text_field_tag :search %>
<%= submit_tag "search" %>
</p>
<% end %>
listings_controller.rb
def index
@listings = Listing.all
@listings = Listing.paginate(:page => params[:page], :per_page => 10)
@user = User.find_by_name(params[:name])
@listing = Listing.find_by_id(params[:id])
@categories = Category.all
@listings = Listing.search(params[:search])
end
end
listing.rb
def self.search(search)
if search
find(:all, :conditions => ['name LIKE ?', "%#{search}%"])
else
find(:all)
end
end
我收到以下錯誤:無法找到帶有'id'的列表=我理解,find方法會立即查找id。 然而,我不知道如何設置它以便搜索我的所有列表。 find_by_all當然不起作用。
我希望有人能提供幫助
謝謝你這么認真
如何修改listing.rb 搜索方法?
def self.search(search)
if search
self.where("name like ?", "%#{search}%")
else
self.all
end
end
加..
listings_controller.rb
def index
@listings = Listing.all
# Patching all Listing
@listing = Listing.where(id: params[:id]) if params[:id].present?
# Find By Id (For pagination, the 'where' statement result is Listing ActiveRecord::Relationship )
@listings = @listings.search(params[:search]) if params[:search].present?
# Search using Keyword
@listings = @listings.paginate(:page => params[:page], :per_page => 10)
# Pagination
@user = User.find_by_name(params[:name]) if params[:name].present?
# Find User using name column
@categories = Category.all
end
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