登錄后出現警報對話框

Question

我的日志記錄異步任務執行登錄過程，它接收用戶輸入，通過webservices發送，驗證它，如果用戶登錄詳細信息正確，則發送會話ID，如果用戶登錄詳細信息錯誤，則不返回任何內容，也返回錯誤，如果用戶登錄信息有誤，我試圖顯示一個警報對話框，我的邏輯是在onPostExecute中包含IF語句，以檢查會話ID字段是否為null，如果為null，它將顯示警報對話框並阻止用戶登錄后無法工作，但是我的問題是，即使用戶輸入正確的詳細信息，它也會很快顯示警報對話框（閃爍），然后將我定向到儀表板，我不希望該警報對話框要顯示即使是幾秒鍾，我認為它還沒有准備好我的IF語句

那就是我的Login.java

    protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState);
    setContentView(R.layout.fragment_login); 
        LB = (Button) findViewById(R.id.loginbutton);
        LB.setOnClickListener(this); 



    }

 public void onClick(View view){

     switch (view.getId()){


      case R.id.loginbutton: //When login button is clicked
      new LongOperation().execute(""); //Starts the method called LongOperation

      break;


     }
    }


    public class LongOperation extends AsyncTask<String, Void, String>{ //string, void, string was added automatically

         @Override
         protected void onPreExecute() {

             super.onPreExecute();
             pdia = new ProgressDialog(Login.this);
             pdia.setMessage("Loading...");
             pdia.show();   

                }   

    @Override
    protected String doInBackground(String... params) {


        SharedPreferences pref = getApplicationContext().getSharedPreferences("MyPref", 0); // 0 - for private mode
        Editor editor = pref.edit();
        editor.clear();
        editor.commit();
              SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 
              usersusername = (EditText)findViewById(R.id.editusername); 
              userspassword = (EditText)findViewById(R.id.editpassword); 

              String user_Name = usersusername.getText().toString(); 
              String user_Password = userspassword.getText().toString();


              editor.putString("username",user_Name); 
              editor.commit();

              PropertyInfo unameProp =new PropertyInfo();
              unameProp.setName("userName");//Define the variable name in the web service method
              unameProp.setValue(user_Name);//set value for userName variable
              unameProp.setType(String.class);//Define the type of the variable
              request.addProperty("username",user_Name);//Pass properties to the variable
      //Using this to add parameters "username" grabbed from WSDL

              PropertyInfo passwordProp =new PropertyInfo();
              passwordProp.setName("password");
              passwordProp.setValue(user_Password);
              passwordProp.setType(String.class);
              request.addProperty(passwordProp);

      SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); // Declare the version of the soap request
      envelope.setOutputSoapObject(request);

      try {
        HttpTransportSE aht = new HttpTransportSE(URL);


        aht.call(SOAP_ACTION, envelope);  


        SoapPrimitive result =(SoapPrimitive)envelope.getResponse();
        String SessionID= result.toString();


        if (!TextUtils.isEmpty(SessionID))
               {
                  Intent intent = new Intent(Login.this,Dashboard.class);
                  startActivity(intent);
               }

      }
      catch (Exception e){
      e.printStackTrace();
      }



    return null; 
    }







    @Override

    protected void onPostExecute(String Something) {

        pdia.dismiss();
        super.onPostExecute(Something);
         if(usersusername.getText().length()==0) {
             usersusername.setError("Please enter your username");
           }
           if(userspassword.getText().length()==0) {
             userspassword.setError("Please enter your password");
           }

    if(Something == null) {


    Builder builder = new Builder(Login.this);
    builder.setMessage("Invalid login details");
    builder.setPositiveButton(R.string.ok_button, null);
              builder.create().show();

                  // show dialog and prepare the fields for retry 


               }


          }  



      } 


     }

Answer 1

在您的Web服務中，創建一個檢查器，就​​像一個整數是否成功，如果成功則查詢1，但不查詢0。 在asynctask中檢索它，然后在成功== 1的情況下簽入執行后，如果成功== 0的調用對話框，則轉到儀表板。

順便說一句，因為AsyncTask容易出現內存泄漏，請嘗試使用新的Android Volley進行網絡連接。 干杯! :)