[英]Unwanted output formatting when passing lists and strings
我受命用python編寫一個程序以適合給定的(且不可更改的)“驅動程序”程序,該程序使Set類由一個稱為“成員”的列表的單個變量組成。
我的問題是方法“ has_subset()”和“ intersect()”的輸出無法正確顯示。 輸出中沒有多余的括號,逗號和撇號。
這是集合類:
class Set:
def __init__(self):
self.members = []
def add_element(self, integer):
if integer not in self.members:
self.members.append(integer)
def remove_element(self, integer):
while integer in self.members: self.members.remove(integer)
def remove_all(self):
self.members = []
def has_element(self, x):
while x in self.members: return True
return False
# probably doesnt work, __repr__
def __repr__(self):
if len(self.members) == 0:
return "{}"
return "{" + ", ".join(str(e) for e in self.members) + "}"
#Same as above, probably doesnt work
def __str__(self):
if len(self.members) == 0:
return "{}"
return "{" + ", ".join(str(e) for e in self.members) + "}"
def __add__(self, other):
counter = 0
while counter < len(other.members):
if other.members[counter] not in self.members:
self.members.append(other.members[counter])
counter = counter + 1
return self.members
def intersect(self, x):
counter = 0
answer = Set()
while counter < len(x.members):
if x.members[counter] in self.members: answer.members.append(x.members[counter])
counter = counter + 1
return answer
#No clue if this is what is intended
def has_subset(self, x):
counter = 0
while counter < len(x.members):
if x.members[counter] not in self.members: return False
counter = counter + 1
return True
這是驅動程序文件:
from Set import *
first = Set()
count = 0
while count < 10:
first.add_element(count)
count += 1
print(first)
second = Set()
count = 5
while count < 15:
second.add_element(count)
count += 1
print(second)
third = Set()
third.add_element(2)
third.add_element(1)
third.add_element(8)
third.add_element(5)
#Tests has_subset with a set that is a subset
if first.has_subset(third):
print(third, "is a subset of", first)
else:
print(third, "is not a subset of", first)
#Tests has_subset with a set that is not a subset
if second.has_subset(third):
print(third, "is a subset of", second)
else:
print(third, "is not a subset of", second)
#Tests overloaded +
fourth = first + second
print(first, "+", second, "=\n", fourth)
#Tests intersect
fifth = first.intersect(second)
print(fifth, "is the intersection of", first, "and\n", second)
這是輸出:
{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
{5, 6, 7, 8, 9, 10, 11, 12, 13, 14}
({2, 1, 8, 5}, 'is a subset of', {0, 1, 2, 3, 4, 5, 6, 7, 8, 9})
({2, 1, 8, 5}, 'is not a subset of', {5, 6, 7, 8, 9, 10, 11, 12, 13, 14})
({0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}, '+', {5, 6, 7, 8, 9, 10, 11, 12, 13, 14}, '=\n', [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14])
({5, 6, 7, 8, 9, 10, 11, 12, 13, 14}, 'is the intersection of', {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}, 'and\n', {5, 6, 7, 8, 9, 10, 11, 12, 13, 14})
請注意,前兩行的格式正確,沒有括號,但是一旦合並了其他字符串,多余的標點符號就會發揮作用。 如何僅通過編輯Set類來刪除此不需要的輸出來創建輸出?
這與Set類無關—問題在於您如何打印內容。
我懷疑您使用的是Python 2.x?
如果是這樣,那么當您執行print(third, "is a subset of", second)
,您實際上是在告訴Python打印元組(包含3個元素)。 Python強制執行並打印括號和逗號,因為這是打印元組的一部分。 print(...)
在Python 2中不是函數。
要解決此問題,您可以手動將每塊添加在一起:
print str(third) + ' is a subset of ' + str(second)
...或使用字符串格式:
print '{} is a subset of {}'.format(third, second)
...或在驅動程序文件頂部的from __future__ import print_function
中添加這一行from __future__ import print_function
以包含Python 3打印語義,這確實將print(...)
轉換為函數並滿足您的要求。
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