[英]Laravel & Mockery: Unit testing the update method without hitting the database
好吧所以我對單元測試,嘲弄和laravel都很陌生。 我正在嘗試對我的資源控制器進行單元測試,但我仍然堅持更新功能。 不確定我做錯了什么或只是想錯了。
這是我的控制器:
class BooksController extends \BaseController {
// Change template.
protected $books;
public function __construct(Book $books)
{
$this->books = $books;
}
/**
* Store a newly created book in storage.
*
* @return Response
*/
public function store()
{
$data = Input::except(array('_token'));
$validator = Validator::make($data, Book::$rules);
if($validator->fails())
{
return Redirect::route('books.create')
->withErrors($validator->errors())
->withInput();
}
$this->books->create($data);
return Redirect::route('books.index');
}
/**
* Update the specified book in storage.
*
* @param int $id
* @return Response
*/
public function update($id)
{
$book = $this->books->findOrFail($id);
$data = Input::except(array('_token', '_method'));
$validator = Validator::make($data, Book::$rules);
if($validator->fails())
{
// Change template.
return Redirect::route('books.edit', $id)->withErrors($validator->errors())->withInput();
}
$book->update($data);
return Redirect::route('books.show', $id);
}
}
這是我的測試:
public function testStore()
{
// Add title to Input to pass validation.
Input::replace(array('title' => 'asd', 'content' => ''));
// Use the mock object to avoid database hitting.
$this->mock
->shouldReceive('create')
->once()
->andReturn('truthy');
// Pass along input to the store function.
$this->action('POST', 'books.store', null, Input::all());
$this->assertRedirectedTo('books');
}
public function testUpdate()
{
Input::replace(array('title' => 'Test', 'content' => 'new content'));
$this->mock->shouldReceive('findOrFail')->once()->andReturn(new Book());
$this->mock->shouldReceive('update')->once()->andReturn('truthy');
$this->action('PUT', 'books.update', 1, Input::all());
$this->assertRedirectedTo('books/1');
}
問題是,當我這樣做時,我得到Mockery\\Exception\\InvalidCountException: Method update() from Mockery_0_Book should be called exactly 1 times but called 0 times.
因為我的控制器中有$book->update($data)
。 如果我要將其更改為$this->books->update($data)
,它將被正確模擬並且不會觸及數據庫,但是當使用前端函數時它會更新我的所有記錄。
我想我只是想知道如何$book-object properly
模擬$book-object properly
。
我清楚了嗎? 別的我知道。 謝謝!
嘗試findOrFail
方法不返回new Book
,而是返回一個模擬對象,而不是它有一個更新方法。
$mockBook = Mockery::mock('Book[update]');
$mockBook->shouldReceive('update')->once();
$this->mock->shouldReceive('findOrFail')->once()->andReturn($mockBook);
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