[英]Beautiful Soup nested div (Adding extra function)
我試圖從[www.quicktransportsolutions.com][1]
提取公司名稱,地址和郵政編碼。 我編寫了以下代碼來亂寫網站並返回我需要的信息。
import requests
from bs4 import BeautifulSoup
def trade_spider(max_pages):
page = 1
while page <= max_pages:
url = 'http://www.quicktransportsolutions.com/carrier/missouri/adrian.php'
source_code = requests.get(url)
plain_text = source_code.text
soup = BeautifulSoup(plain_text)
for link in soup.findAll('div', {'class': 'well well-sm'}):
title = link.string
print(link)
trade_spider(1)
運行代碼后,我看到了我想要的信息,但我很困惑如何在沒有所有非相關信息的情況下進行打印。
在上面
print(link)
我以為我可以讓link.string拉公司名稱,但那失敗了。 有什么建議么?
輸出:
div class="well well-sm">
<b>2 OLD BOYS TRUCKING LLC</b><br><a href="/truckingcompany/missouri/2-old-boys-trucking-usdot-2474795.php" itemprop="url" target="_blank" title="Missouri Trucking Company 2 OLD BOYS TRUCKING ADRIAN"><u><span itemprop="name"><b>2 OLD BOYS TRUCKING</b></span></u></a><br> <span itemprop="address" itemscope="" itemtype="http://schema.org/PostalAddress"><a href="http://maps.google.com/maps?q=227+E+2ND,ADRIAN,MO+64720&ie=UTF8&z=8&iwloc=addr" target="_blank"><span itemprop="streetAddress">227 E 2ND</span></a>
<br>
<span itemprop="addressLocality">Adrian</span>, <span itemprop="addressRegion">MO</span> <span itemprop="postalCode">64720</span></br></span><br>
Trucks: 2 Drivers: 2<br>
<abbr class="initialism" title="Unique Number to identify Companies operating commercial vehicles to transport passengers or haul cargo in interstate commerce">USDOT</abbr> 2474795 <br><span class="glyphicon glyphicon-phone"></span><b itemprop="telephone"> 417-955-0651</b>
<br><a href="/inspectionreports/2-old-boys-trucking-usdot-2474795.php" itemprop="url" target="_blank" title="Trucking Company 2 OLD BOYS TRUCKING Inspection Reports">
大家,
感謝您的幫助到目前為止...我正在嘗試為我的小爬蟲添加額外的功能。 我寫了以下代碼:
def Crawl_State_Page(max_pages):
url = 'http://www.quicktransportsolutions.com/carrier/alabama/trucking-companies.php'
while i <= len(url):
response = requests.get(url)
soup = BeautifulSoup(response.content)
table = soup.find("table", {"class" : "table table-condensed table-striped table-hover table-bordered"})
for link in table.find_all(href=True):
print link['href']
Output:
abbeville.php
adamsville.php
addison.php
adger.php
akron.php
alabaster.php
alberta.php
albertville.php
alexander-city.php
alexandria.php
aliceville.php
alpine.php
... # goes all the way to Z I cut the output short for spacing..
我想在這里完成的是用city.php拉出所有href並將其寫入文件。 ..但是現在,我陷入了一個無限循環,它不斷循環通過URL。 有關如何增加它的任何提示? 我的最終目標是創建另一個函數,通過www.site.com/state/city.php反饋到我的trade_spider,然后循環遍歷所有50個日期...有效的東西
while i < len(states,cities):
url = "http://www.quicktransportsolutions.com/carrier" + states + cities[i] +"
然后這將循環到我的trade_spider函數,拉出我需要的所有信息。
但是,在我到達那個部分之前,我需要一些幫助來擺脫我的無限循環。 有什么建議么? 或者我將要遇到的可預見的問題?
我試圖創建一個循環遍歷頁面上每個鏈接的爬蟲,然后如果它在頁面上發現trade_spider可以抓取的內容,它會將其寫入文件...但是,這有點超出我的技能現在設定。 所以,我正在嘗試這種方法。
我會依賴每個公司的不同標簽的itemprop
屬性。 它們可以方便地設置name
, url
, address
等:
import requests
from bs4 import BeautifulSoup
def trade_spider(max_pages):
page = 1
while page <= max_pages:
url = 'http://www.quicktransportsolutions.com/carrier/missouri/adrian.php'
response = requests.get(url)
soup = BeautifulSoup(response.content)
for company in soup.find_all('div', {'class': 'well well-sm'}):
link = company.find('a', itemprop='url').get('href').strip()
name = company.find('span', itemprop='name').text.strip()
address = company.find('span', itemprop='address').text.strip()
print name, link, address
print "----"
trade_spider(1)
打印:
2 OLD BOYS TRUCKING /truckingcompany/missouri/2-old-boys-trucking-usdot-2474795.php 227 E 2ND
Adrian, MO 64720
----
HILLTOP SERVICE & EQUIPMENT /truckingcompany/missouri/hilltop-service-equipment-usdot-1047604.php ROUTE 2 BOX 453
Adrian, MO 64720
----
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.