CakePHP使用選擇條件從多個表中檢索數據

Question

我正在使用CakePHP構建應用程序，但我陷入了使用一系列聯接檢索數據的問題。 在下面的簡化示例中，使用別名Delivery的聯接可能具有多個記錄，我想帶回該表中特定字段中的最大值的記錄。

$inv_conditions = array(    'Invoice.invoice_date >=' => $DateFormatter->dateForDB($dateFrom), 
                 'Invoice.invoice_date <=' => $DateFormatter->dateForDB($dateTo),
                 'Invoice.id >' => 385380 );    

$join   =   array(array(
                'table' => 'jobs',
                'alias' => 'Jobs',
                'type'  => 'LEFT',
                'conditions'    => array('Invoice.job_id = Jobs.JOB_ID' ) 
              ),    
            array(
                'table' => 'functional',
                'alias' => 'Delivery',
                'type'  => 'LEFT'
                'conditions'=> array('AND ' => array('Invoice.job_id = Delivery.JOB',
                                                     'Delivery.TYPE_STAGE = 1') 
                            )
                     )

        );    

$invoices = $this->Invoice->find("all", array(
                "fields"    =>  array(
                            'Invoice.id',
                            'Invoice.job_id',
                            'Invoice.invoice_no',
                            'Invoice.consolidated_type',
                            'Invoice.customer_id_tbc',
                            'Invoice.invoice_date',
                            'Invoice.invoice_reference',
                            'Invoice.invoice_req',
                            'Jobs.PAYMENT_TYPE',
                            'Jobs.CUSTOMER',
                            'Jobs.MOST_RELEVANT_LINE',
                            'Delivery.DEPARTURE_DATE',
                            'Delivery.CNOR_CNEE_NAME',
                            'Delivery.TOWN_NAME',
                              ),
                "conditions"    =>  $inv_conditions,
                "joins"     => $join
                )
            );

}

我可以使用SQL做到這一點，如下所示：

SELECT 
    jobs.JOB_ID, 
    jobs.CUSTOMER, 
    functional.JOB_LINE_ORDER, 
    functional.CNOR_CNEE_NAME, 
    functional.TOWN_NAME 
FROM jobs JOIN functional ON
            jobs.JOB_ID = 'M201409180267'
        AND 
            functional.JOB =  jobs.JOB_ID
        AND 
            functional.TYPE_STAGE = 0 
        AND 
            functional.JOB_LINE_ORDER = 
               (SELECT MAX(JOB_LINE_ORDER) FROM functional 
                WHERE functional.JOB = 'M201409180267' AND functional.TYPE_STAGE = 0) 

我嘗試對條件數組使用以下內容：

'conditions'    =>    array('AND ' => 
                           array( 'Invoice.job_id = Delivery.JOB',
                                  'Delivery.TYPE_STAGE = 1'
                                  'Delivery.JOB_LINE_ORDER = MAXIMUM(Delivery.JOB_LINE_ORDER)' )
                            )

這確實會帶來結果，但不會帶來正確的結果，並且Cake生成的結果SQL的where子句中確實具有select。 在蛋糕中檢索數據時，有沒有一種方法可以使其中創建的sql語句在where子句中具有select。

任何建議將不勝感激。 謝謝巴斯

Answer 1

您需要使用子查詢在where子句中生成選擇。 您可以在模型中創建一個執行此操作的方法，然后從控制器中調用它。

$subQuery = $db->buildStatement(
            array(
                'fields'     => array(''),
                'table'      => $db->fullTableName($this),
                'alias'      => 'aliasName',
                'limit'      => null,
                'offset'     => null,
                'joins'      => array(),
                'conditions' => $conditionsArray,
                'order'      => null,
                'group'      => null
            ),
            $this
        );
        $subQuery = ' <<YOUR MAIN QUERY CONDITION (' . $subQuery . ') >>';
        $subQueryExpression = $db->expression($subQuery);

        $conditions[] = $subQueryExpression;
        return $this->Model->find('list', compact('conditions'));