PHP逐步驗證用戶輸入數據

Question

我對PHP相當陌生，現在我不得不在我的公司找到合適的程序員的同時用PHP編寫小型程序。

我編寫了一個使用表單數據（姓名，電子郵件，手機號碼等）的程序，然后檢查輸入的數據是否有效。 我的代碼工作正常，但是它們沒有遵循任何過程（即，它檢查所有驗證）。 我希望它首先檢查一個條件（例如電子郵件）是否有效，然后僅檢查下一個條件（電話號碼）。 如果無效，則返回一些錯誤消息並停止執行其余代碼。

我已經嘗試了很多東西，但是都沒有成功，這是示例代碼

  
 
  
  
  
 
   
 
    
<?php include("includes/functions.php"); ?>
<?php include("includes/dbconnection.php"); ?>
	
<?php
	//I've done this in main.php page but also had to do it in functions.php page too...
	$First_Name = $_POST['first_name'];
	$Last_Name = $_POST['last_name'];
	$Phone_Number = $_POST['phone_number'];
	$E_Mail = $_POST['email'];
	$User_ID = $_POST['user_id'];
?>	
	
<?php $user_id_validation = validate_user_id($User_ID); ?>
<?php $phone_number_validation = validate_phone_number(); ?>
<?php $all_fields_validation = validate_all_fields(); ?>

<?php 
	//This is dbconnection.php page
	define("DB_SERVER", "localhost");
	define("DB_USER", "root");
	define("DB_PASS", "some_password");
	define("DB_NAME", "some_db");

	 
	  $connection = mysqli_connect(DB_SERVER, DB_USER, DB_PASS, DB_NAME); //This $connection has been used as global in function.php 
	  
	  if(mysqli_connect_errno()) {
		die("Database connection failed: " . 
			 mysqli_connect_error() . 
			 " (" . mysqli_connect_errno() . ")"
		);
	  }
?>
<?php
	//This is functions.php
	function validate_user_id($User_ID) {
		global $connection;
		
		$sql = "SELECT * FROM users WHERE user_id = '$User_ID'";
		$result = mysqli_query($connection,$sql);
		$num_row = mysqli_num_rows($result);
		if ($num_row == 1) {
		$User_ID = $num_row['user_id'];
		echo "user verification passed! ";
		} else {
			echo "You are not authorized to perform this action! ";
		}
		return false;
	}
	
	function validate_phone_number() {
		$Phone_Number = $_POST['phone_number'];
		$check_phone_number = substr($phone_number, 0, -7); //Take first 3 digits of phone number to validate if its standard phone number
				
		if (strlen($Phone_Number) != 10) {
			echo "Invalid Phone Number";
		} elseif ($check_phone_number === "740") {
			echo "Phone Number is valid ";
		} else {
			echo "Invalid Phone Number, please check again! ";
		}
	}
		
	function validate_all_fields() {
		$First_Name = $_POST['first_name'];
		$Last_Name = $_POST['last_name'];
		$Phone_Number = $_POST['phone_number'];
		$E_Mail = $_POST['email'];
		$User_ID = $_POST['user_id'];
		
		if (!empty($E_Mail)
		&& !empty($Phone_Number) 
		&& !empty($First_Name)
		&& !empty($Last_Name))
		
		) {
			echo "All fields entered, you can proceed. ";
		} else {	
			echo "E_Mail, Phone Number, First Name and Last Name must be entered!"; 
		}
	}
	// Database Insertion
	function Insert_Into_Table () {
		global $connection;
		$First_Name = $_POST['first_name'];
		$Last_Name = $_POST['last_name'];
		$Phone_Number = $_POST['phone_number'];
		$E_Mail = $_POST['email'];
		$User_ID = $_POST['user_id'];
		
		$sql = "INSERT INTO some_tbl(User_ID, First_Name, Last_Name, Phone_Number, E_Mail)
				VALUES ('$User_ID', '$First_Name', '$Last_Name', '$Phone_Number', '$E_Mail')";
		
		$result = mysqli_query($connection, $sql);
			
	}
	
?>
 
   
 
  

Answer 1

嘗試這個。 我不確定您是否想要這個。

if(!is_email($email))
{
    echo 'Invalid email!!';
    exit();
}
elseif(!is_phone($phone)) 
{
    echo 'Invalid Phone!!';
    exit();
}
else {
   //success code
}

然后創建一個名為功能is_email()和寫驗證代碼，而返回true ，如果它是在電子郵件格式，否則返回false

 is_email($email)
 {
     //validation code
 }