[英]create xml from java object using JAXB
大家好,我有java對象,我必須將其轉換為xml。 例如這樣的課程
package com.test.xml;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Customer {
String name;
int age;
public String getName() {
return name;
}
@XmlElement
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
@XmlElement
public void setAge(int age) {
this.age = age;
}
}
並轉換為xml
package com.test.xml;
import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
public class JAXBExample {
public static void main(String[] args) {
Customer customer = new Customer();
customer.setName("testName");
customer.setAge(25);
try {
File file = new File("C:\\testXml.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(customer, file);
jaxbMarshaller.marshal(customer, System.out);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
這將創建這樣的xml
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<customer>
<age>25</age>
<name>testName</name>
</customer>
和我的問題。 如何從這樣的客戶對象創建xml?
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<customer>
<customerInfo>
<age>25</age>
<name>testName</name>
</customerInfo>
</customer>
1.創建一個客戶類
2.創建一個CustomerInfo類
3.客戶有CustomerInfo
4.現在使用Jaxb創建您的xml文件。
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