在兩個HTML和PHP之間交換變量

Question

我正在嘗試對mikrotik熱點進行匯總，此設備不允許在其中使用PHP，並且我需要將設備中的變量攜帶到外部php頁面中，以保存客戶數據並啟用試用版在熱點...

在此設備內，它托管了一個包含以下代碼的HTML頁面

<html>
<head><title>...</title></head>
<body>
$(if chap-id)
<noscript>
<center><b>JavaScript required. Enable JavaScript to continue.</b></center>
</noscript>
$(endif)
<center>If you are not redirected in a few seconds, click 'continue' below<br>
<form name="redirect" action="http://10.2.3.100/cadastro.html?mac=$(mac)" method="post">
<input type="hidden" name="mac" value="$(mac)">
<input type="hidden" name="ip" value="$(ip)">
<input type="hidden" name="username" value="$(username)">
<input type="hidden" name="link-login" value="$(link-login)">
<input type="hidden" name="link-orig" value="$(link-orig)">
<input type="hidden" name="error" value="$(error)">
<input type="hidden" name="chap-id" value="$(chap-id)">
<input type="hidden" name="chap-challenge" value="$(chap-challenge)">
<input type="hidden" name="link-login-only" value="$(link-login-only)">
<input type="hidden" name="link-orig-esc" value="$(link-orig-esc)">
<input type="hidden" name="mac-esc" value="$(mac-esc)">
<input type="submit" value="continue">
</form>
<script language="JavaScript">
<!--
    document.redirect.submit();
//-->
</script></center>
</body>
</html>

我學會了在google中搜索，可以將變量發送到另一頁，方法是將其插入URL的末尾，所以好的，我將發送開始試用所需的變量$ MAC。

接收它的頁面是用HTML編寫的表單頁面，我無法在該頁面中接收該變量，我需要接收該變量以發送到另一頁面，在PHP中，最后一個將在MySQL中保存表單並在發送之后到Mikrotik與客戶端MAC的鏈接，使其可以在Internet中瀏覽。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>CADASTRO DE CLIENTES COM BANCO DE DADOS E PHP</title>
<style type="text/css">


</head>

<body>
<p id="demo"></p>
<script type"text/javascript">
var qs = new QueryString();
var v1 = qs.get("mac");
document.getElementById("demo").innerHTML = v1;
</script>


<form id="cadastro" name="cadastro" method="post" action="cadastro.php" onsubmit="return validaCampo(); return false;">
  <table width="625" border="0">
    <tr>
      <td width="69">Nome:</td>
      <td width="546"><input name="nome" type="text" id="nome" value="$(mac)" size="70" maxlength="60" />
        <span class="style1">*</span></td>
    </tr>
    <tr>
      <td>Email:</td>
      <td><input name="email" type="text" id="email" size="70" maxlength="60" />
      <span class="style1">*</span></td>
    </tr>

    <tr>
      <td colspan="2"><p>
        <input name="cadastrar" type="submit" id="cadastrar" value="Concluir meu Cadastro!" /> 
        <br />
          <input name="limpar" type="reset" id="limpar" value="Limpar Campos preenchidos!" />
          <br />
          <span class="style1">* Campos com * s&atilde;o obrigat&oacute;rios!          </span></p>
      <p>&nbsp; </p></td>
    </tr>
  </table>
</form>
</body>
</html>

現在，PHP頁面

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
</head>

<body>
<?php 
// RECEBENDO OS DADOS DO PC DO USUARIO
   $mac=$_POST['mac'];

// RECEBENDO OS DADOS PREENCHIDOS DO FORMULÁRIO !
$nome   = $_POST ["nome"];  //atribuição do campo "nome" vindo do formulário para variavel  
$email  = $_POST ["email"]; //atribuição do campo "email" vindo do formulário para variavel

//Gravando no banco de dados !

//conectando com o localhost - mysql
$conexao = mysql_connect("localhost","root","senha");
if (!$conexao)
    die ("Erro de conexão com localhost, o seguinte erro ocorreu -> ".mysql_error());
//conectando com a tabela do banco de dados
$banco = mysql_select_db("cadhotspot",$conexao);
if (!$banco)
    die ("Erro de conexão com banco de dados, o seguinte erro ocorreu -> ".mysql_error());



$query = "INSERT INTO `clientes` ( `nome` , `email`  ) 
VALUES ('$nome', '$email', '$sexo' '')";

mysql_query($query,$conexao);

echo "Seu cadastro foi realizado com sucesso!<br>Agradecemos a atenção.";
?>
Mac: <?php echo $mac ?><br>

<meta http-equiv="refresh" content="60; url=<?php echo $linkloginonly; ?>?dst=<?php echo $linkorigesc; ?>&username=T-<?php echo $mac; ?>">


</body>
</html>

這個想法是，從MikroTik從客戶設備接收MAC到托管在其中的HTML頁面，然后將帶有表單的HTML頁面加載到客戶singup，當客戶單擊發送時，它將寫入mysql並發回下面的鏈接去米克羅蒂克

 <meta http-equiv="refresh" content="60; url=http://10.5.50.1?&username=T-<?php echo $mac; ?>">

我的整個問題是在HTML與HTML之間以及PHP頁面之后交換變量。

Answer 1

要將mac的值轉發到php頁面，請嘗試在表單內添加以下JS代碼。 這將創建一個隱藏字段，提交后會將mac值發布到php頁面。

<script type="text/javascript">
var qs = new QueryString();
var v1 = qs.get("mac");
document.write('<input type="hidden" name="mac" value="' + v1  + '">')
</script>

html頁面中缺少一些結束標記。

在兩個HTML和PHP之間交換變量

問題描述

1 個解決方案

解決方案1
0 2014-09-24 15:17:15

在兩個HTML和PHP之間交換變量

問題描述

1 個解決方案

解決方案1 0 2014-09-24 15:17:15

解決方案1
0 2014-09-24 15:17:15