[英]SQL, how to sum two sums from two different queries
我試圖在兩個不同的條件下獲取相同變量的總和。 只是想知道是否有辦法將它們加在一起。 查詢的細節並不是很相關。 基本上只是嘗試將第一個和與第二個和相加。
例如 -
首先查詢:
select sum(amt_tot)
from agbgift, aprdclb
where agbgift_id = '1' and agbgift_id = aprdclb_id
第二個查詢:
select sum(amt_tot)
from agbgift, aprxref, aprdclb where
aprxref_id = '1' and
agbgift_id = aprxref_xref_id and
aprxref_id = aprdclb_id and
xref_code in ('SPS','BUS','ORG','OWN','FDN' );
我正在尋找的最終結果是“第一查詢總和” +“第二查詢總和”
在這種情況下,就這么簡單:
SELECT
/* Query 1 (in parentheses) */
(select sum(amt_tot)
from agbgift, aprdclb
where agbgift_id = '1' and agbgift_id = aprdclb_id)
+ /* plus */
/* Query 2 (also in parentheses) */
(select sum(amt_tot)
from agbgift, aprxref, aprdclb where
aprxref_id = '1' and
agbgift_id = aprxref_xref_id and
aprxref_id = aprdclb_id and
xref_code in ('SPS','BUS','ORG','OWN','FDN' ))
with子句很容易,如果with不能正常工作,則可以在from子句中使用別名
with b ( select sum(amt_tot) as bsum
from agbgift, aprxref, aprdclb where
aprxref_id = '1' and
agbgift_id = aprxref_xref_id and
aprxref_id = aprdclb_id and
xref_code in ('SPS','BUS','ORG','OWN','FDN' ))
, a (select sum(amt_tot) asum
from agbgift, aprdclb
where agbgift_id = '1' and agbgift_id = aprdclb_id )
select a.asum + b.bsum
from a, b
在這種情況下確實是這樣:
select a.asum + b.bsum
from (select sum(amt_tot) asum
from agbgift, aprdclb
where agbgift_id = '1' and agbgift_id = aprdclb_id) as a,
( select sum(amt_tot) as bsum
from agbgift, aprxref, aprdclb where
aprxref_id = '1' and
agbgift_id = aprxref_xref_id and
aprxref_id = aprdclb_id and
xref_code in ('SPS','BUS','ORG','OWN','FDN' )) as b
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