[英]I am getting NoSuchBeanDefinitionexception while creating a simple Spring Boot project with JpaRepository
[英]NoSuchBeanDefinitionException while building a simple Spring JPA project
我遵循以下教程: https : //spring.io/guides/gs/accessing-data-jpa/
我正在使用maven,Spring和JPA創建一個基於示例內存的數據庫。 我有以下課程;
型號類別:
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
@Entity
public class Customer {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private long id;
public long getId() { return this.id; }
public void setId(long Id) { this.id = Id; }
private String firstName;
public String getFirstName() { return this.firstName; }
public void setFirstName(String FirstName) { this.firstName = FirstName; }
private String lastName;
public String getLastName() { return this.lastName; }
public void setLastName(String LastName) { this.lastName = LastName; }
public Customer(String firstname, String lastname) {
super();
this.firstName = firstname;
this.lastName = lastname;
}
public Customer() {
super();
}
@Override
public String toString() {
return String.format(
"Customer[id=%d, firstName='%s', lastName='%s']",
id, firstName, lastName);
}
}
客戶資源庫類
import java.util.List;
import org.springframework.data.repository.CrudRepository;
import com.accenture.cursojava.modelos.Customer;
public interface CustomerRepository extends CrudRepository<Customer, Long>{
List<Customer> findByLastName(String lastName);
}
應用類別:
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.context.ConfigurableApplicationContext;
import org.springframework.context.annotation.Configuration;
import com.accenture.cursojava.dataaccess.CustomerRepository;
import com.accenture.cursojava.modelos.Customer;
@Configuration
@EnableAutoConfiguration
public class Application {
public static void main(String[] args) {
ConfigurableApplicationContext context = SpringApplication.run(Application.class, args);
CustomerRepository repository = context.getBean(CustomerRepository.class);
repository.save(new Customer("Cliente", "de Prueba 1"));
repository.save(new Customer("Cliente", "de Prueba 2"));
repository.save(new Customer("Cliente", "de Prueba 3"));
repository.save(new Customer("Cliente", "de Prueba 4"));
repository.save(new Customer("Cliente", "de Prueba 1"));
repository.save(new Customer("Cliente", "de Prueba 2"));
repository.save(new Customer("Cliente", "de Prueba 3"));
repository.save(new Customer("Cliente", "de Prueba 4"));
Iterable<Customer> clientes = repository.findAll();
for (Customer customer : clientes) {
System.out.println(customer.getFirstName());
System.out.println(customer.getLastName());
}
Iterable<Customer> clientes1 = repository.findByLastName("de Prueba 1");
for (Customer customer : clientes1) {
System.out.println(customer.getFirstName());
System.out.println(customer.getLastName());
}
context.close();
}
}
執行完代碼並按照教程指出的完全進行操作之后,我得到以下輸出:
Exception in thread "main" org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type [com.myapplication.CustomerRepository] is defined
at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBean(DefaultListableBeanFactory.java:319)
at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:987)
at com.myapplication.Application.main(Application.java:18)
有什么想法可能是罪魁禍首?
Spring對此bean的CustomerRepository一無所知。 您需要告訴Spring這是一個托管bean。 您可以通過添加@Repository批注來實現。
@Repository
public interface CustomerRepository extends CrudRepository<Customer, Long>{
List<Customer> findByLastName(String lastName);
}
您可能還需要告訴Spring在哪里查找帶注釋的類(盡管@EnableAutoConfiguiration可能使此操作變得不必要-我不熟悉它)
@Configuration
@EnableAutoConfiguration
@EnableJpaRepositories()//specify the base package containing your repository interfaces.
public class Application {
}
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