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帶有Tomcat 8的OpenJPA。無法創建EntityManager

[英]OpenJPA with Tomcat 8. Unable to create EntityManager

我一直試圖使用非jta數據源使我的JPA(openJPA)應用程序與Tomcat一起使用。

我正在使用Maven,沒有IDE。 只是在Windows上的vi,主要是為了了解事物如何真正起作用並融合在一起

這是我得到的錯誤(我已經在SO上研究了類似的問題,但找不到修復程序)

Caused by: java.lang.RuntimeException: <openjpa-2.3.0-r422266:1540826 fatal user error> org.apache.openjpa.persistence.ArgumentException: The persistence provider is attempting to use properties in the persistence.xml file to resolve the data source. A Java Database Connectivity (JDBC) driver or data source class name must be specified in the openjpa.ConnectionDriverName or javax.persistence.jdbc.driver property. The following properties are available in the configuration: "org.apache.openjpa.jdbc.conf.JDBCConfigurationImpl@442ce698".

這是我的persistence.xml文件

    <?xml version="1.0" encoding="UTF-8"?>
<persistence 
    version="2.1" 
    xmlns="http://xmlns.jcp.org/xml/ns/persistence" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">

    <persistence-unit name="CricketScorer" transaction-type="RESOURCE_LOCAL">

        <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>

        <non-jta-data-source>java:/comp/env/jdbc/scoringdb</non-jta-data-source>

        <class>com.mantr.cricket.scorer.server.persistence.entities.Account</class>
        <class>com.mantr.cricket.scorer.server.persistence.entities.Delivery</class>
        <class>com.mantr.cricket.scorer.server.persistence.entities.DeliveryPK</class>
        <class>com.mantr.cricket.scorer.server.persistence.entities.Match</class>
        <class>com.mantr.cricket.scorer.server.persistence.entities.Player</class>
        <class>com.mantr.cricket.scorer.server.persistence.entities.Team</class>
    </persistence-unit>
</persistence>

這是Tomcat的context.xml文件

 <?xml version="1.0" encoding="UTF-8"?>

<Context>
<!--  JDBC Data source for the scoring database -->
    <Resource name="jdbc/scoringdb" 
              auth="Container"
              type="javax.sql.DataSource" 
              username="b888446f2789ce" 
              password="28fa221e"
              driverClassName="com.mysql.jdbc.Driver"
              url="jdbc:mysql://us-cdbr-east-06.cleardb.net/heroku_17744ef452a6a8d"
              maxActive="10" 
              maxIdle="4"/>
</Context>

還有Web.xml文件

    <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
     version="2.5">



    <servlet>
        <servlet-name>cxf</servlet-name>
        <display-name>cxf</display-name>
        <description>Apache CXF Endpoint</description>
        <servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>cxf</servlet-name>
        <url-pattern>/services/*</url-pattern>
    </servlet-mapping>

    <resource-ref>
            <description>Scoring Database</description>
            <res-ref-name>jdbc/scoringdb</res-ref-name>
            <res-type>javax.sql.DataSource</res-type>
            <res-auth>Container</res-auth>
  </resource-ref>


</web-app>

當我嘗試使用JNDI初始上下文打開連接時,此方法有效。 因此,我認為JNDI數據源已正確配置

請參閱我的個人自動管理的Tomcat webapp OpenJPA2.x包裝器。 查看jdbc名稱,您可能在其中包含一個額外的“ /”字符? https://github.com/Murmur/ScopedEntityManager/blob/master/example_webapp/webapp/WEB-INF/classes/META-INF/persistence.xml

<non-jta-data-source>java:/comp/env/jdbc/scoringdb</non-jta-data-source>
<non-jta-data-source>java:comp/env/jdbc/test</non-jta-data-source>

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