[英]input file empty handling
所以,我有一個表格,它是文章表格,其中有標題,內容,圖像(用於顯示使用javascript從輸入中選擇的圖像)和輸入(用於選擇圖像),我使用
$upload_errors = array(
// http://www.php.net/manual/en/features.file-upload.errors.php
UPLOAD_ERR_OK => "No errors.",
UPLOAD_ERR_INI_SIZE => "Larger than upload_max_filesize.",
UPLOAD_ERR_FORM_SIZE => "Larger than form MAX_FILE_SIZE.",
UPLOAD_ERR_PARTIAL => "Partial upload.",
UPLOAD_ERR_NO_FILE => "No file.",
UPLOAD_ERR_NO_TMP_DIR => "No temporary directory.",
UPLOAD_ERR_CANT_WRITE => "Can't write to disk.",
UPLOAD_ERR_EXTENSION => "File upload stopped by extension."
);
檢查我的輸入文件是否有錯誤,並且可以很好地添加新文章...
但是,如果我想編輯我的文章怎么辦? 通常我會重復使用相同的表格,但是回顯所選文章的值並顯示所有內容,它顯示標題,內容,圖像,但不包含輸入文件,並且我知道這是安全問題,因此,例如,我只想更改文章標題,因為我提交了包括輸入文件在內的所有表單內容,因此將出現錯誤“無文件” ...那么這種問題是否有最佳實踐? 也許有一些方法可以識別是否我沒有選擇任何圖像,那么我只會通過它而不顯示任何錯誤...
這是我如何處理錯誤
$error = $_FILES['upload_file']['error'];
if ($error != 1) {
$information->id = $_POST['id'];
$information->name = $_POST['name'];
$name = $_POST['name'];
$information->upload_image($_FILES['upload_file']['tmp_name']);
$content = $_POST['content'];
$entity_content = htmlentities($content);
$entity_content = stripslashes(str_replace('\r\n', '',$entity_content));
$information->content = $entity_content;
try{
if($information->save()){
if(isset($_POST['simpan'])){
redirect_to("show_information.php");
}
}else{
$message = "failed to change information";
}
}catch(PDOException $e){
$message = "failed to change information";
error_notice($e);
}
}else{
$message = $upload_errors[$error];
}
所以,如果沒有輸入,我需要怎么做才能繞過錯誤檢查?
所以我只是為此得到了最好的解決方案。。。。
$error = $_FILES['upload_file']['error'];
if ($error == 0 || $error == 4) {
if($error != 4)
//do the uploading
}
在上載/保存類中,我只需要檢查
if(!empty($image))
// do move_uploaded_to
// do the saving with replacement of $image
else
// do the saving without $image
$ image只是我將圖像名稱/路徑放入mysql數據庫的占位符
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