[英]rails select in activerecord I can not understand
我該如何選擇:“選擇日期,觸發器ID,嚴重性,狀態,types.name,收件人從日志,類型WHERE logs.type_id = types.id;”? 我有talble日志,其中“ type_id”列包含(1,2,2,3,3,1 ...),我需要將sql選擇為:(email,sms,sms,voice,voice,email ... ),其中“類型”表包含id(1,2,3),name(電子郵件,sms,語音)
遷移:
create_table :logs, id: false do |t|
t.integer :date, unsigned: true
t.integer :triggerid, unsigned: true
t.integer :severity, unsigned: true
t.integer :status, unsigned: true
t.integer :type_id, unsigned: true
t.string :recipient, limit: 100
create_table :types do |t|
t.string :name, limit: 7
end
1.遷移:
1.1。 日志表
class CreateLogs < ActiveRecord::Migration
def change
create_table :logs do |t|
t.integer :date, unsigned: true
t.integer :triggerid, unsigned: true
t.integer :severity, unsigned: true
t.integer :status, unsigned: true
t.integer :type_id, unsigned: true
t.string :recipient, limit: 100
t.references :type
t.timestamps
end
end
end
類型表:
class CreateTypes < ActiveRecord::Migration
def change
create_table :types do |t|
t.string :name, limit: 7
t.timestamps
end
end
end
1.3。 rake db:migrate
2.型號:
class Log < ActiveRecord::Base
belongs_to :type
end
class Type < ActiveRecord::Base
has_many :logs #or has_one, I don't know your app logic
end
現在,您可以通過“ type_id”選擇日志的實例。
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